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Roman55 [17]
3 years ago
14

The moisture in hot, humid, stagnant air surrounding a cold-water pipeline continually diffuses to the cold surface where it con

denses. The condensed water forms a liquid film around the pipe, and then continuously drops off the pipe to the ground below. At a distance of 10 cm from the surface of the pipe, the moisture content of the air is constant. Close to the pipe, the moisture content of the air approaches the vapor pressure of water evaluated at the temperature of the pipe
What is the simplest differential form of Fick's flux equation for water vapor, NA?
Engineering
1 answer:
VladimirAG [237]3 years ago
6 0

Answer:

The simplest differential form of Fick's flux equation for water vapor is

\frac{1}{r} \frac{d}{dr} (rN_{rA} )=0

Explanation:

Fick's law has to do with the density of the particles is proportional to their concentration gradient. For this question some assumptions will be taken into account:

-The pipe is considered to be very long and diffusion only occurs in the r direction.

-The reaction is not homogeneous, therefore RA = 0

-The concentration of the component A is constant

-No mixing, only diffusion

Due to the complexity of the terms used in solving the Fick equation, the solution is found in the attached file.

Download docx
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Lubov Fominskaja [6]

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The radiation's penetration power and exposure to the image receptor both increase as the kVp value is raised.

<h3>Exposure to the image receptor is enhanced with an increase in kVp, right?</h3>

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5 0
1 year ago
Read two numbers from user input. Then, print the sum of those numbers. Hint -- Copy/paste the following code, then just type co
Softa [21]

Answer:

I am Providing Answer in C Language Program.

Explanation:

Please find attachment regarding code of taking two numbers input and adding them.

I would like to recommend you please use software which supports C language.

#include <stdio.h>

int main () {

int a, b, sum;

printf ("\ nEnter two no:");

scanf ("% d% d", & d, & e);

sum1 = d + e;

printf ("Sum:% d", sum1);

return (0);

}

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3 years ago
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Answer:

Explanation:

In order to keep your car running at its best, it’s important to keep up with routine maintenance and inspections. By properly maintaining your vehicle, you’ll reduce future repair costs, optimize your car’s performance, maintain its value and extend its life. Here are some regular maintenance needs to keep in mind for your vehicle:

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This assignment is designed to test your understanding of graphical user interface components and Event Driven programming in Ja
lys-0071 [83]

Answer:

Java program is given below

Explanation:

JavaPadGUI.java

package javapad.gui;

import java.awt.BorderLayout;

import java.awt.Container;

import java.awt.Dimension;

import java.awt.event.ActionEvent;

import java.awt.event.ActionListener;

import java.awt.event.WindowAdapter;

import java.awt.event.WindowEvent;

import java.io.File;

import java.io.FileNotFoundException;

import java.io.PrintWriter;

import java.util.Scanner;

import javax.swing.JButton;

import javax.swing.JFrame;

import javax.swing.JLabel;

import javax.swing.JOptionPane;

import javax.swing.JPanel;

import javax.swing.JScrollPane;

import javax.swing.JTextArea;

public class JavaPadGUI extends JFrame implements ActionListener{

  //constants

  private static final String TITLE = "Macrosoft JavaPad XP";

  private static final String SLOGAN = "Macrosoft: Resistance is futile";

 

  //button names

  private static final String NEW = "New";

  private static final String LOAD = "Load";

  private static final String SAVE = "Save";

  private static final String QUIT = "Quit";

 

  private static final String FILENAME = "hardcode.txt";

  //messages

 

  private static final String QUIT_MSG = "Quitting, Save?";

  private static final String LOAD_ERR = "Could not access file " + FILENAME;

 

 

  //fields

  private JTextArea txtContent;

  private JButton butNew, butLoad, butSave, butQuit;

 

  public JavaPadGUI()

  {

      super(TITLE);

      createUI();

      setSize(new Dimension(400, 300));

      setDefaultCloseOperation(EXIT_ON_CLOSE);

         

  }

 

  private void createUI()

  {

      Container c = getContentPane();

      c.setLayout(new BorderLayout(30,30));

     

      //create the buttons panel

      JPanel butPanel = new JPanel();

      butPanel.add(butNew = new JButton(NEW));

      butPanel.add(butLoad = new JButton(LOAD));

      butPanel.add(butSave = new JButton(SAVE));

      butPanel.add(butQuit = new JButton(QUIT));

     

      //set command names for the buttons, these will be when button is clicked

      butNew.setActionCommand(NEW);

      butLoad.setActionCommand(LOAD);

      butSave.setActionCommand(SAVE);

      butQuit.setActionCommand(QUIT);

     

      JPanel sloganPanel = new JPanel();

      sloganPanel.add(new JLabel(SLOGAN));

     

      //create textarea with scrollbar

      txtContent = new JTextArea(15, 25);

      txtContent.setLineWrap(true);

         

      JScrollPane scroll = new JScrollPane(txtContent);

     

      //now add all components

      c.add(butPanel, BorderLayout.NORTH);

      c.add(scroll, BorderLayout.CENTER);

      c.add(sloganPanel, BorderLayout.SOUTH);

     

     

      //set the actionlistner to buttons to handle button click event

      butNew.addActionListener(this);

      butLoad.addActionListener(this);

      butSave.addActionListener(this);

      butQuit.addActionListener(this);

     

  }

  public void actionPerformed(ActionEvent e)

  {

      String cmd = e.getActionCommand();

      if(cmd.equals(NEW))

          txtContent.setText("");

      else if (cmd.equals(LOAD))

          load();

      else if(cmd.equals(SAVE))

          save();

      else if (cmd.equals(QUIT))

          quit();

  }

  private void quit()

  {

      int option = JOptionPane.showConfirmDialog(this, QUIT_MSG);

      if(option == JOptionPane.YES_OPTION)

      {

          save();

      }

     

      System.exit(0);

  }

 

  private void save()

  {

      try {

          PrintWriter w = new PrintWriter(new File(FILENAME));

          w.write(txtContent.getText());

          w.close();

      } catch (FileNotFoundException e) {

          JOptionPane.showMessageDialog(this,"I/O Error", LOAD_ERR, JOptionPane.ERROR_MESSAGE);

      }

             

  }

  private void load()

  {

      try {

          Scanner s = new Scanner(new File(FILENAME));

          String str = "";

          while(s.hasNextLine())

              str += s.nextLine();

          txtContent.setText(str);

          s.close();

      } catch (FileNotFoundException e) {

          JOptionPane.showMessageDialog(this, LOAD_ERR, "I/O Error",JOptionPane.ERROR_MESSAGE);

      }

     

  }

}

RunJavaPad.java

package javapad;

import javapad.gui.JavaPadGUI;

public class RunJavaPad {

  public static void main(String[] args) {

      JavaPadGUI gui = new JavaPadGUI();

      gui.setVisible(true);

  }

}

7 0
3 years ago
A rod that was originally 100-cm-long experiences a strain of 82%. What is the new length of the rod?
Ierofanga [76]

Answer: (b)

Explanation:

Given

Original length of the rod is L=100\ cm

Strain experienced is \epsilon=82\%=0.82

Strain is the ratio of the change in length to the original length

\Rightarrow \epsilon =\dfrac{\Delta L}{L}\\\\\Rightarrow 0.82=\dfrac{\Delta L}{100}\\\\\Rightarrow \Delta L=82\ cm

Therefore, new length is given by (Considering the load is tensile in nature)

\Rightarrow L'=\Delta L+L\\\Rightarrow L'=82+100=182\ cm

Thus, option (b) is correct.

8 0
3 years ago
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