All categories

4 years ago

1. An arrow signal with a left-pointing arrow_

Engineering

2 answers:

Paul [167]4 years ago

6 0

Answer:b

Explanation:It’s only applies to the left-turning traffic

Whitepunk [10]4 years ago

5 0

Answer:

correct option is B. only applies to left-turning traffic

Explanation:

solution

according to traffic rule regulation , when we see signal with left pointing arrow it mean that we can move on the left side turn

and if we see left pointing signal with red arrow it meaning same as NO TURN ON RED

and when we see yellow arrow it also means the same as the yellow light

and if there is green arrow it mean we can freely now move on left

so here correct option is B. only applies to left-turning traffic

You might be interested in

Which statement about tensile stress is true? A. Forces that act perpendicular to the surface and pull an object apart exert a t

svp [43]

Answer:

A. Forces that act perpendicular to the surface and pull an object apart exert a tensile stress on the object.

Explanation:

Tensile stress is referred as a deforming force, in which force acts perpendicular to the surface and pull an object apart, attempting to elongate it.

The tensile stress is a type of normal stress, in which a perpendicular force creates the stress to an object’s surface.

Hence, the correct option is "A."

3 0

3 years ago

A binary star system consists of two stars of masses m1m1m_1 and m2m2m_2. The stars, which gravitationally attract each other, r

d1i1m1o1n [39]

Answer:

$a_c_2=\dfrac{a_c_1\times m_1}{m_2}$

Explanation:

The question is: <em>Find the magnitude of the centripetal acceleration of the star with mass m₂</em>

The <em>centripetal acceleration</em> is the quotient of the centripetal force and the mass.

$a_c=\dfrac{F_c}{m}$

Thus, you can write the equations for each star:

$a_c_1=\dfrac{F_c_1}{m_1}$

$a_c_2=\dfrac{F_c_2}{m_2}$

As per Newton's third law, the centripetal forces are equal in magnitude. Then:

$a_c_1\times m_1=a_c_2\times m_2$

Now you can clear $a_c_2$ :

$a_c_2=\dfrac{a_c_1\times m_1}{m_2}$

6 0

4 years ago

Three identical fatigue specimens (denoted A, B, and C) are fabricated from a nonferrous alloy. Each is subjected to one of the

Law Incorporation [45]

Answer:

B A and C

Explanation:

Given:

Specimen σ $_{max}$ σ $_{min}$

A +450 -150

B +300 -300

C +500 -200

Solution:

Compute the mean stress

σ $_{m}$ = (σ $_{max}$ + σ $_{min}$ )/2

σ $_{mA}$ = (450 + (-150)) / 2

= (450 - 150) / 2

= 300/2

σ $_{mA}$ = 150 MPa

σ $_{mB}$ = (300 + (-300))/2

= (300 - 300) / 2

= 0/2

σ $_{mB}$ = 0 MPa

σ $_{mC}$ = (500 + (-200))/2

= (500 - 200) / 2

= 300/2

σ $_{mC}$ = 150 MPa

Compute stress amplitude:

σ $_{a}$ = (σ $_{max}$ - σ $_{min}$ )/2

σ $_{aA}$ = (450 - (-150)) / 2

= (450 + 150) / 2

= 600/2

σ $_{aA}$ = 300 MPa

σ $_{aB}$ = (300- (-300)) / 2

= (300 + 300) / 2

= 600/2

σ $_{aB}$ = 300 MPa

σ $_{aC}$ = (500 - (-200))/2

= (500 + 200) / 2

= 700 / 2

σ $_{aC}$ = 350 MPa

From the above results it is concluded that the longest fatigue lifetime is of specimen B because it has the minimum mean stress.

Next, the specimen A has the fatigue lifetime which is shorter than B but longer than specimen C.

In the last comes specimen C which has the shortest fatigue lifetime because it has the higher mean stress and highest stress amplitude.

7 0

4 years ago

When you want to make a right turn your car must be

Eduardwww [97]

Answer:

(Have a great day)

¶Emma Jess¶

Explanation:

Get as far to the right side of the road as possible. Do not cut the across lanes of traffic to performed any turn..

8 0

3 years ago

A piston-cylinder assembly contains 2 lb of air at a temperature of 540 degrees R and a pressure of 1 atm. The air is compressed

attashe74 [19]

Answer:

$W=-123.8Btu$

Explanation:

Hello,

In this problem, the piston-cylinder assembly make us state the energy balance as:

$Q-W=\Delta U$

Thus, we must now compute $\Delta U$ in terms of Cv as follows:

$\Delta U=mCv(T_2-T_1)\\\Delta U=2lb*0.173\frac{Btu}{lb*R}*(840R-540R)\\ \Delta U=103.8Btu$

Now, since heat is given off, its sign is negative, thus, the work is computed as:

$W=Q-\Delta U\\W=-20Btu-103.8Btu=-123.8Btu$

This work means that work was done over the system in order to allow the compression.

The suppositions were:

- The change in the internal energy is a function of the temperature.

- Air is an ideal gas.

Best regards.

8 0

4 years ago