Michael took the return trip at a velocity 33.75 miles per hour.
<h3>How fast did Michael drive in his return trip?</h3>
Let suppose that Michael drove in <em>straight line</em> road and at <em>constant</em> velocity. Therefore, the speed of the vehicle (v), in miles per hour, can be defined as distance traveled by the vehicle (d), in miles, divided by travel time (t), in hours.
First trip
45 = s / 3 (1)
Second trip
v = s / 4 (2)
By (1) and (2):
45 · 3 = 4 · v
v = 33.75 mi / h
Michael took the return trip at a velocity 33.75 miles per hour.
To learn more on velocities: brainly.com/question/18084516
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I pretty sure you would use x over 38.00 = 20 over 100 then cross multiply them
Answer:
m=9
Step-by-step explanation:
11-9m=-70
-11 -11
-9m = -81
divide both sides by -9 and you get m=9
Answer:
Depends
Step-by-step explanation:
All triangles have 3 sides no more no less Hope this helps
