First let's write out the inequality before choosing a graph.
x apples each weighing 1/3 of a pound: 1/3x
y pounds of grapes: y
So...
1/3x + y < 5
The maximum weight is 4 pounds since the total weight of both the grapes and apples are less than 5.
In the y-axis, the first, third, and fourth graphs already exceed the capacity of 5 pounds.
So, by process of elimination, the correct graph for this problem is the second one.
Answer:
24 and 21 are the two numbers
Step-by-step explanation:
let n represent the unknown number
let n-3 represent the second unknown number
n+n-3 = 45
2n-3=45
2n=45+3
2n=48
n=48/2
n=24
n-3=21
CHECK: 24+21=45
.˙. the first number is 24 and the second number with a difference of 3 is 21
18.47 is the answer when you add them together
Answer:
The frequency of oranges is the classroom is 47.37%.
Step-by-step explanation:
The relative frequency of oranges is the number of oranges divided by the total number of fruits.
We have that:
8 students brought 2 apples each. So there are 8*2 = 16 apples
4 students brought an apple and an orange each. So there are 16 + 4*1 = 20 apples and 4*1 = 4 oranges.
7 students brough 2 oranges each. So there are 4 + 2*7 = 18 oranges.
There are 18 oranges, and 20+18 = 38 fruits in total.
So the frequency of oranges in the classrom is
