There are two possibilities for this question:
1- The shopping cart is at rest (not moving):
In this case:
∑Forces = 0
Force exerted by Jim + Force exerted by cart = 0
2 + Force exerted by cart = 0
Force exerted by cart = -2
2- The cart is moving as a result of a net force "m":
In this case:
∑Forces = m
Force exerted by Jim + Force exerted by cart = m
Force exerted by cart = m-2
The voltage across all the resistors is the same i.e 120V
Each element of the parallel circuit has the same voltage applied to it. The total current flowing from the source is equal to the sum of the currents across each path. The electric potential difference (V) across each resistor in a parallel circuit is the same. Ohm's law states that I = V / R applies to the current in a resistor. The current will be lowest where the resistance is highest since the V is the same for each resistor. The currents passing through each resistor in a parallel combination have the same voltage across them because of their different resistance values and the laws of Ohms i., If two or more components are connected in parallel, they will be having same difference of potential (voltage) across their ends Parallel circuits are then used as current dividers.
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Explains how and why nature does<span> what it </span>does<span>. ... A </span>scientific<span> law is a statement based on repeated experimental observations that ...
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The net displacement at a point on the string where the pulses cross is 0.2 m.
The term "displacement" refers to a shift in an object's position. It has a magnitude and a direction, making it a vector quantity. An arrow pointing from the starting point to the finishing point serves as its symbol.
A string that is connected to a post at one end is used to transmit a sequence of pulses, each measuring 0.1 meters in amplitude.
At the post, the pulses are reflected and return along the string without losing any of their amplitude.
Now, let's say the ends are free.
There is no inversion on reflection if the end is free. The amplitude at their intersection is 2A.
Now, since A = 0.1 m
Then, 2A = 2(0.1) = 0.2 m
As a result, the net displacement at the string's intersection of two pulses is 0.2 m.
The correct option is (c).
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