A baby carriage is sitting at the top of a hill that is 21 m high. The carriage with the baby weighs 12 N. The carriage has pote
1 answer:
The gravitational potential energy is 252 J
Explanation:
The Gravitational Potential Energy (GPE) of an object is given by
where
W is the weight of the object
h is the height of the object above the ground
For the carriage and the baby in this problem, we have
W = 21 N is their weight
h = 21 m is their height above the ground
Substituting,
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(a) The ball will accelerate at a speed of 9.81 m/s² while it is in flight.
(b) The ball will be moving at a speed of 0 m/sec when it reaches its highest point.
(c) The ball's initial upward velocity is 20.30 m/s.
(d) It will reach a maximum height of 21.0 m.
<h3 /><h3>What is speed?</h3>Speed is defined as the change in distance with regard to time. A scalar quantity, speed. It is a temporal element, m/sec is its unit.
The information provided in the issue is;
u is the fall's beginning speed in m/sec;
h is the fall's distance
g is the fall's acceleration or 9.81 m/sec²
a. The ball's speed while in flight is equal to the acceleration caused by gravity, which is 9.81 m/s².
b. When the ball reaches its highest point, its velocity will be zero.
c. The ball's starting velocity is;
v=u-gt
0=u-gt
u=gt
u=9.81 m/s² × 2.07 sec
u=20.30 m/s
d. The formula is used to determine the highest height it can reach.
As a result, the ball's greatest height, beginning velocity, and acceleration are all 9.81 meters per second, zero meters per second, 20.30 meters per second, and 21 meters accordingly.
To learn more about the velocity, refer to the link: brainly.com/question/862972.
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1) The law of motion of the projectile is
To find the velocity, we should compute the derivative of h(t):
So now we can calculate the speed at t=2 s and t=4 s:
The negative sign in the second speed means the projectile has already reached its maximum height and it is now going downward.
2) The projectile reaches its maximum height when the speed is equal to zero:
So we have
And solving this we find
3) To find the maximum height, we take h(t) and we just replace t with the time at which the projectile reaches the maximum height, i.e. t=2.30 s:
4) The time at which the projectile hits the ground is the time at which the height is zero: h(t)=0. So, this translates into
This is a second-order equation, and if we solve it we get two solutions: the first solution is negative, so we can ignore it since it's physically meaningless; the second solution is
And this is the time at which the projectile hits the ground.
5) The velocity of the projectile when it hits the ground is the velocity at time t=4.68 s:
with negative sign, because it is directed downward.
To find the velocity, we should compute the derivative of h(t):
So now we can calculate the speed at t=2 s and t=4 s:
The negative sign in the second speed means the projectile has already reached its maximum height and it is now going downward.
2) The projectile reaches its maximum height when the speed is equal to zero:
So we have
And solving this we find
3) To find the maximum height, we take h(t) and we just replace t with the time at which the projectile reaches the maximum height, i.e. t=2.30 s:
4) The time at which the projectile hits the ground is the time at which the height is zero: h(t)=0. So, this translates into
This is a second-order equation, and if we solve it we get two solutions: the first solution is negative, so we can ignore it since it's physically meaningless; the second solution is
And this is the time at which the projectile hits the ground.
5) The velocity of the projectile when it hits the ground is the velocity at time t=4.68 s:
with negative sign, because it is directed downward.
Answer:
t = 2 seconds
Explanation:
In 2nd question, the question is given the attached figure.
Initial speed of the bus, u = 0
Acceleration of the bus, a = 8 m/s²
Final speed, v = 16 m/s
We need to find the time taken by the car to reach the stop. Acceleration of an object is given by :
t is time taken
The bus will take 2 seconds to reach the stop.
