I. Positive acceleration increases velocity. Negative acceleration decreases velocity. runner A sped up until the finish line and then slowed to a stop.
ii. Zero a acceleration implies a constant, unchanging velocity not a zero velocity. runner B achieved some velocity prior to 8s and is moving and must slow down to reach a stop.
iii. None. No aspects of this reasoning are correct. Everything she says is wrong. See iv for what/why.
iv. The sign on acceleration denotes the direction of *change in velocity* not change in direction. The sign on velocity can denote change in direction but only “forward” or “reverse” along a particular path. Cardinal direction is not indicated, generally, by the sign on velocity. It may correspond to North/South situationally but it is not an built-in feature of velocity and its sign. For example, if you are traveling with positive velocity and turn left to continue your journey you still have a positive velocity in the new direction. In fact, if you turn left again, traveling in the opposite direction as the one you started with your velocity would still be positive… in the new direction. The velocity relative to original direction could be said to be negative but that would be a confusing way to describe a journey. Maybe if you stopped the vehicle and moved in reverse, you could meaningfully say velocity was negative.
Answer:
given,
R = 2i + j+3k
a) magnitude in x = 2
y = 1
z = 3
b) magnitude of R
R = 3.74 units
c) angle between the R and the x, y, and z axes.
θ x = 57.72°
θ y = 74.51°
θ z = 36.68°
Answer:
Higher.
Explanation:
The greater the frequency the bigger the amplitude gets and the greater pitch gets.
Think - more energy, bigger waves, more waves, and higher sound
Answer:
Breh seriously. Ugh fine.
1.B
2.D
3.C
4.C
5.D,A and B
6.A,C and D
227kj Because The first thing to do here is to calculate the energy of a single photon of wavelength equal to
527 nm
, then use Avogadro's number to scale this up to the energy of a mole of such photons.
