All categories

2 years ago

Greg has $56. Tom has $17 more than Greg. Jason has 8 less than Tom.How much money dose Jason has

2 answers:

8 0

Since tom has 17 more than Greg we would add 17 to 56 which would get us 73. So we know that Tom has $73. Now to find how much money Jason has we would subtract 8 (because he has 8 less or - Jason) from the amounts tom has so:

56+17= 73
73-8= 65

aev [14]2 years ago

6 0

Jason had $65
56+17-8

You might be interested in

What is the image point of (0,-9)after a translation right 5 units and down 1 unit?

nekit [7.7K]

Answer:

I think 0 -10 or mabe 0,-11

6 0

2 years ago

Express as a unit rate. $18.50 for 5 lbs

m_a_m_a [10]

Answer:

3.7 dollars per lb

7 0

2 years ago

Read 2 more answers

A factory-made 100,000 jars of peanut butter. 50,000 of the jars contained creamy peanut butter. What percentage of the jars of

snow_tiger [21]

Answer:

50%

hope this answer helps you!

3 0

3 years ago

You are planning a survey of starting salaries for recent business major graduates from your college. From a pilot study you est

xxTIMURxx [149]

Answer:

1245

Step-by-step explanation:

-Given the standard deviation is $9000 and the margin of error is $500.

-the minimum sample size at a 95% confidence level can be calculated using the formula:

$n\geq( \frac{z\sigma}{MOE})^2\\\\\\\geq (\frac{1.96\times 9000}{500})^2\\\\\\\geq 1244.6784\approx 1245$

Hence, the minimum sample size is 1245

*Since there's no data fromw which we are drawing our variables, we can manually input our parameters in excel and calculate as attached.

5 0

2 years ago

Suppose that documentation lists the average sales price of a single-family home in the metropolitan Dallas/Ft. Worth/Irving, Te

Julli [10]

Answer:

"0.0373" seems to be the appropriate solution.

Step-by-step explanation:

The given values are:

n₁ = 43

n₂ = 35

$\bar{x_1}=217800$

$\bar{x_2}=204700$

$\sigma_1=30300$

$\sigma_2=33800$

Now,

The test statistic will be:

⇒ $Z=\frac{\bar{x_1}-\bar{x_2}}\sqrt{\frac{\sigma_1^2}{n_1} +\frac{\sigma_2^2}{n_2} }$

On substituting the given values in the above formula, we get

⇒ $=\frac{217800-204400}{\sqrt{\frac{(30300)^2}{43} +\frac{(33800)^2}{35} } }$

⇒ $=\frac{217800-204400}{\sqrt{\frac{918090000}{43} +\frac{1142440000}{35} } }$

⇒ $=\frac{13400}{7347.93}$

⇒ $=1.7828$

then,

P-value will be:

= $P(Z>1.7828)$

= $0.0373$

8 0

2 years ago