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Afina-wow [57]
3 years ago
11

Solve for X 3ax/5 - 4c = ax/5

Mathematics
1 answer:
NISA [10]3 years ago
5 0
\frac { 3ax }{ 5 } -4c=\frac { ax }{ 5 }
First multiply both sides by 5:
5\cdot (\frac { 3ax }{ 5 } -4c)=5\cdot \frac { ax }{ 5 } \\ 3ax-20c=ax
then take the ax to the other side :
3ax-20-ax=0 and simplify:
2ax-20c=0 factor:
2(ax-10c)=0\\ ax-10c=0\\ ax=10c\\ x=\frac { 10c }{ a }
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Simplify completely x^2+4x-45 / x^2+10x+9
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Step-by-step explanation:

This algebraic fraction

The task to be performed here is factorisation and simplification. Now going by the question,

x² + 4x - 45/x² + 10x + 9, the factorisation of

x² + 4x - 45 = x² + 9x - 5x - 45

= x(x + 9 ) - 5(x + 9 )

= ( x + 9 )(x - 5 ), don't forget this is the algebraic fraction's Numerator

The second part

x² + 10x + 9 = x² + x + 9x + 9

= x(x + 1) + 9( x + 1 )

= ( x + 9 )( x + 1 ), this is the algebraic denominator.

Now place the second expression which is the denominator under the first expression which is the numerator.

( x + 9 )( x - 5 )/( x + 9 )( x + 1 ).

You can see that, ( x + 9 )/( x + 9 ) divide each other , therefore therr then cancelled and left with

x - 5/x + 1

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