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Sergio039 [100]
3 years ago
8

Besides color, what other factors do designers consider when coming up with winning color combos?

Chemistry
1 answer:
Kitty [74]3 years ago
5 0

Answer:

Consider your personal preferences first because the colors you use in your home need to reflect those preferences as well as fit in with your lifestyle.

Light has an influence over the colors that can make them look stunning as well as dull. Different types of light sources such as incandescent, fluorescent, halogen, or LED will affect the way a color appears.

The orientation of the room such as the direction it faces or how much natural or artificial light is available can also affect how colors will appear in the room. So, consider the room specifications as well.

Consider fixed as well as furnished elements and accessories as they too have color. Take them into consideration to ensure that camouflaging or clashing doesn’t happen.

Consider the texture of walls whether they are smooth, rough, or in between. The texture will change the appearance of the color. Smooth walls will appear lighter while rough walls will appear darker.

Consider the kind of mood you want to set in a particular room. Different colors as well as their hues and combinations emote different feelings.

Consider the finishing if the paint whether to use gloss, semi-gloss, or satin to name a few. The finish of the t will have a lot to do with the final look of your color.

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A very simple assumption for the specific heat of a crystalline solid is that each vibrational mode of the solid acts independen
MatroZZZ [7]

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4.7 kJ/kmol-K

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Using the Debye model the specific heat capacity in kJ/kmol-K

c = 12π⁴Nk(T/θ)³/5

where N = avogadro's number = 6.02 × 10²³ mol⁻¹, k = 1.38 × 10⁻²³ JK⁻¹, T = room temperature = 298 K and θ = Debye temperature = 2219 K  

Substituting these values into c we have

c = 12π⁴Nk(T/θ)³/5  

= 12π⁴(6.02 × 10²³ mol⁻¹)(1.38 × 10⁻²³ JK⁻¹)(298 K/2219 K)³/5

= 9710.83(298 K/2219 K)³/5

= 1942.17(0.1343)³

= 4.704 J/mol-K

= 4.704 × 10⁻³ kJ/10⁻³ kmol-K

= 4.704 kJ/kmol-K

≅ 4.7 kJ/kmol-K

So, the specific heat of diamond in kJ/kmol-K is 4.7 kJ/kmol-K

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Answer:

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BIonary bi means 2

i hope this helps :)

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