A.) 7^4x = 10
log base 10 (7^4X) = log base 10 (10)
4x log base 10 (7) = 1
4x (0.8451) = 1
3.3804x = 1
x = 0.2958
b.) ln(2) + ln(4x-1) = 5
ln (2 * 4x-1) = 5
ln (8x-2) = 5
log base (3) (8x-2) = 5
e^5 = 8x-2
e^5+2 = 8x
x = 18.8016
Answer:
it would be 14
radius=diameter÷2=38÷2=14
Answer:
i) 20m/s
ii) 4s
iii) 144m
iv) 2 m/s
Step-by-step explanation:
Please see attached picture for full solution.
<span>Group A (distance in miles) 1 1.5 3.03 3.2 2.8 1.5 1.8 2.5 2.2
Group B (distance in miles) 2 2.5 3.23 1.3 1.8 2.4 3 1.5 1.8
Group A mean = (1 + 1.5 + 3.03 + 3.2 + 2.8 + 1.5 + 1.8 + 2.5 + 2.2)/9 = 19.53/9 = 2.17
Group B mean = (2 + 2.5 + 3.23 + 1.3 + 1.8 + 2.4 + 3 + 1.5 + 1.8)/9 = 19.53/9 = 2.17
Therefore, the mean is equal for Group A and Group B.
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Answer:
2 pieces (that each equal 1/3 of the whole bar)
