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Kruka [31]
3 years ago
12

WWhat do these substances have in common?

Chemistry
2 answers:
olga2289 [7]3 years ago
8 0

Answer; Option A is correct

Explanation:

  • Matter is substance which is made up of atoms
  • Matter is a substance which occupies physical space

All the given four substance are matter :

  • Apple juice is a mixture.
  • Helium gas is a pure substance.
  • Salt water is mixture.
  • Copper wire is a pure substance.

But all of them are composed of atoms.


Mariana [72]3 years ago
4 0

The answer is that they are Pure substances

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The mass of Zr deposited in the process is 41.4 g.

<h3>What is electrolytic cell?</h3>

An electrolytic cell is a chemical cell which produces electrical energy by non-spontaneous chemical processes.

From the question;

Zr^4+(aq) + 4e ------> Zr(s)

We know that;

91 g of Zr is deposited by 4(96500) C

xg of Zr is deposited by (7.92 × 6.16 × 60 × 60) C

xg = 91 g ×  (7.92 × 6.16 × 60 × 60) C/4(96500) C

x g = 41.4 g

Learn more about electrolysis: brainly.com/question/12054569

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2 years ago
Sodium chloride (NaCI) is made from _____ of sodium (Na) and ___ of chlorine ( Ci)
astra-53 [7]
Sodium chloride is made from one sodium atom and one chlorine atom:

Sodium has a charge of +1, or just +.

Chlorine has a charge of -1, or just -.

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Find the potentials of the following electrochemical cell:
melomori [17]

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Here Cd undergoes oxidation by loss of electrons, thus act as anode. nickel undergoes reduction by gain of electrons and thus act as cathode.

E^0_(Cd^{2+}/Cd)=-0.40V[/tex]

E^0_(Ni^{2+}/Ni)=-0.24V[/tex]

Cd+Ni^{2+}\rightarrow Cd^{2+}+Ni

Here Cd undergoes oxidation by loss of electrons, thus act as anode. nickel undergoes reduction by gain of electrons and thus act as cathode.

E^0=E^0_{cathode}- E^0_{anode}

Where both E^0 are standard reduction potentials.

E^0=E^0_{[Ni^{2+}/Ni]}- E^0_{[Cd^{2+}/Cd]}

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Using Nernst equation :

E_{cell}=E^o_{cell}-\frac{0.0592}{n}\log \frac{[Cd^{2+}]}{[Ni^{2+]}

where,

n = number of electrons in oxidation-reduction reaction = 2

E^o_{cell} = standard electrode potential = 0.16 V

E_{cell}=0.16-\frac{0.0592}{2}\log \frac{[0.10]}{[0.5]}

E_{cell}=0.18V

Thus the potential of the following electrochemical cell is 0.18 V.

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