When it comes to equilibrium reactions in chemistry, there are a lot of equilibrium constants that can be used. In the case of solubility, the appropriate one to use is the equilibrium constant of solubility product denotes as Ksp. This is the concentration of products raised to their coefficients. For example,
cC ⇔ aA + bB
Ksp = {[A^a][B^b]}
Now, for the this problem, the reaction is
BaSO₄ ⇔ Ba²⁺ + SO₄²⁻
The reaction is already balanced. Since we don't know the value of Ba²⁺ and SO₄²⁻, let's denote this at x.
1.1 × 10⁻¹⁰ = [x][x] =[x²]
[x] = [Ba²⁺] = [SO₄²⁻] = [BaSO₄] = 1.049 × 10⁻⁵ M
500 J (I've had the same question before so I know what answers there are... lol)
Hello
The balance chemical reaction is 2Al + 6HCl -à 2AlCl3 + 3H2 Assuming excess amount of HCl because it is not given Mole Al reacted = 13.5 g ( 1 mole/ 27 g) = 0.5 mole Al
Mole H2 = 0.5 mol Al ( 3 mole H2 / 2 mole Al) = 0.75 mole H2
since at STP then 1 mole gas occupies 22.414 L volume H2 = 0.75 mole (22.414 L / mol) = 16.8105 L H2
Have a nice day
