Answer:
the initial concentration of SCN- in the mixture is 0.00588 M
Explanation:
The computation of the initial concentration of the SCN^- in the mixture is as follows:
As we know that
As it is mentioned in the question that KSCN is present 10 mL of 0.05 M
So, the total milimoles of SCN^- is
= 10 × 0.05
= 0.5 m moles
The total volume in mixture is
= 45 + 10 + 30
= 85 mL
Now the initial concentration of the SCN^- is
= 0.5 ÷ 85
= 0.00588 M
hence, the initial concentration of SCN- in the mixture is 0.00588 M
Where are the following elements to choose from?
<span>The solution to the problem is as follows:
125/58.69 = 2.12 mol
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Therefore, there are 2.12 moles of <span>nickel (Ni) atoms are in 125 g Ni.
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Answer:
Explanation:
concentration unit relates moles of solute to volume of solution. ... First find the number of moles of KCl in the 25.00 mL of 0.500 M solution: ... 13) What volume of 1.25 M sulfuric acid is needed to dissolve 0.750 g of ... mL of 0.0962 M hydrochloric acid is titrated with a calcium hydroxide solution, and ...
