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lozanna [386]
3 years ago
15

Which phrase best describes a metallic bond?

Physics
2 answers:
aalyn [17]3 years ago
6 0
Metallic bonding<span> is the force of attraction between valence electrons and the metal ions. It is the sharing of many detached electrons between many positive ions, 
 
                           Hopefully this can help you understand

</span>
Tresset [83]3 years ago
4 0
Metallic bonding<span> is the force of attraction between valence electrons and the metal ions. It is the sharing of many detached electrons between many positive ions, where the electrons act as a "glue" giving the substance a definite structure.

</span>
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Given that the distance from the left end of the string to the first antinode is 27.5 cm , calculate the wavelength of the stand
ivolga24 [154]

Answer:

= 0.55 m

Explanation:

A standing wave is characterized by anti-nodes and nodes.

Antinodes are points on a standing wave at maximum amplitude, while nodes are points on the standing wave that are stationary and have zero amplitude.

The distance between two adjacent nodes or two adjacent anti-nodes is equivalent to half the wavelength.

Therefore, in this case the half wavelength is 27.5 cm.

Thus, wavelength = 27.5 × 2

                              = 55 cm

                             <u>= 0.55 m</u>

6 0
2 years ago
The Hubble Space Telescope (HST) orbits 569 km above Earth’s surface. If HST has a tangential speed of 7,750 m/s, how long is HS
deff fn [24]

Answer: 5,640 s (94 minutes)

Explanation:

the tangential speed of the HST is given by

v=\frac{2\pi r}{T} (1)

where

2\pi r is the length of the orbit

r is the radius of the orbit

T is the orbital period

In our problem, we know the tangential speed: v=7,750 m/s. The radius of the orbit is the sum of the Earth's radius and the distance of the HST above Earth's surface:

r=6.38\cdot 10^6 m+569,000 m=6.95\cdot 10^6 m

So, we can re-arrange equation (1) to find the orbital period:

T=\frac{2 \pi r}{v}=\frac{2 \pi (6.95\cdot 10^6 m/s)}{7,750 m/s}=5,640 s

Dividing by 60, we get that this time corresponds to 94 minutes.

6 0
3 years ago
Read 2 more answers
A woman can row her canoe at 2.5 m/s. If she faces an opposing current of 3.0 m/s, how fast will she go forward?
taurus [48]

Answer:

V = - 0.5 [m/s]

Explanation:

In order to solve this problem, we must use the principle of relative speeds. This is for an observer who is on the edge of the river he can see how the river moves to the left and the woman tries to move to the right but can not since:

V_{total}=-3+2.5\\V_{total}=-0.5 [m/s]

That is, the person sees how the woman moves to the left but with avelocity of 0.5 [m/s] to the left

8 0
2 years ago
Viewed moving objects from pond water under his microscope and named them “animalcules”.
galben [10]
Anton Von Leeuwenhoek, in the early 1600s, saw these tiny microbes and called them "animalcules" and "wee beasties".
5 0
3 years ago
Two tugboats are moving a barge. Tugboat A pushes on the barge with a force of 3000n. Tugboat B pulls with a force of 5000 Newto
kenny6666 [7]

The net force on the barge is 8000 N

Explanation:

In order to find the net force on the badge, we have to use the rules of vector addition, since force is a vector quantity.

In this problem, we have two forces:

  • The force of tugboat A, F_A = 3000 N, acting in a certain direction
  • The force of tugboat B, F_B = 5000 N, also acting in the same direction

Since the two forces act in the same direction, this means that we can simply add their magnitudes to find the net combined force on the barge. Therefore, we get

F=F_A+F_B = 3000 + 5000 = 8000 N

and the direction is the same as the direction of the two forces.

Learn more about forces:

brainly.com/question/11179347

brainly.com/question/6268248

#LearnwithBrainly

5 0
3 years ago
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