Answer:
MnO₄⁻ + 2 H₂O + 3 e⁻ ⇒ MnO₂ + 4 OH⁻
2 moles of H₂O are on the reactant side.
Explanation:
Let´s consider the following half-reaction.
MnO₄⁻ ⇒ MnO₂
This reduction of permanganate to manganese dioxide happens in a neutral medium. The oxidation number of Mn changes from +7 to +4. When we are in a neutral medium, we can balance the reaction using the ion-electron method either as we were in acid or in basic medium. In this case, to satisfy the condition is the task (<em>water on the reactant side</em>) we will balance this half-reaction as if it were in basic media. Since Mn is already balanced, we have to balance O. We will add as many moles of water as excess of oxygen there is on 1 side, and the double of OH⁻ on the other side. Finally, we add as many electrons as we need to balance it electrically.
MnO₄⁻ + 2 H₂O + 3 e⁻ ⇒ MnO₂ + 4 OH⁻
Dependent is a variable who's outcome depends on another variable. independent is a variable who's outcome doesn't depend on another variable only the researchers experimenting.
hope this helps !
The critical point is said to be the end point of a phase diagram. The most known example is the liquid-vapor critical point, the point in a PT curve that signifies that at this point both vapor and liquid coexist. The critical point is characterized by a critical pressure and a critical temperature.
Water, because electrolysis is using electricity to break the bond of water to release 2 Hydrogens and the 1 Oxygen.
