<span>We can solve this problem by assuming that the decay of
cyclopropane follows a 1st order rate of reaction. So that the
equation for decay follows the expression:</span>
A = Ao e^(- k t)
Where,
A = amount remaining at
time t = unknown (what to solve for) <span>
Ao = amount at time zero = 0.00560
M </span><span>
<span>k = rate constant
t = time = 1.50 hours or 5400 s </span></span>
The rate constant should
be given in the problem which I think you forgot to include. For the sake of
calculation, I will assume a rate constant which I found in other sources:
k = 5.29× 10^–4 s–1 (plug in the correct k value)
<span>Plugging in the values
in the 1st equation:</span>
A = 0.00560 M * e^(-5.29 × 10^–4 s–1 * 5400 s )
A = 3.218 <span>× 10^–4 M (simplify
as necessary)</span>
salt and water solution is a homogeneous mixture
<u>Explanation:</u>
Homogeneous mixtures generally termed as solutions, have an identical similar occurrence and form throughout (the prefix "homo" means the same). Solutions consist of particles as tiny as fragments or molecules. For instance, a sugar solution is homogeneous because only transparent liquids can be seen. Homogeneous mixtures only have individual phase: gas, liquid or solid.
Solvent: normally the material in the greater amount. The material used to dissolve the solute or solutes. Example: water.
Solute: ordinarily the substance in the lesser amount. The substance dissolved by the solvent. Example: salt
Salt and water solution is homogeneous because only transparent liquids can be seen.
Molar mass NH3 = 17.031 g/mol
1 mole NH3 -------------- 17.031 g
?? moles NH3 ---------- 346 g
346 x 1 / 17.031
=> 20.31 moles of NH3
The reaction for burning of charcoal or complete combustion is as follows:

From the above balanced reaction, 1 mole of carbon releases 1 mole of
gas.
Converting mass of charcoal into moles as follows:

Molar mass of pure carbon is 12 g/mol thus,

The same moles of
is released. Converting these moles into mass as follows:
m=n×M
Molar mass of
is 44 g/mol thus,

Converting mass into kg,

Thus, total mass of gas released is 5.5 kg.