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GarryVolchara [31]
3 years ago
12

Hydrogen cab be obtained economically as a byproduct in the electrolysis of____________

Chemistry
1 answer:
yarga [219]3 years ago
4 0
Water, because electrolysis is using electricity to break the bond of water to release 2 Hydrogens and the 1 Oxygen.
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Which substance is a reducing agent?<br><br> A. CO<br> B. F2<br> C. CO2<br> D. H2O2<br> E. FeSO4
IRISSAK [1]

H2O2

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6 0
3 years ago
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When the products of a reaction are hotter than the reactants:
kobusy [5.1K]
A.) The reaction is Exothermic
5 0
3 years ago
How many mL of 2M stock solution would I use to prepare 0.500 L of 0.1 M NaCl?
nordsb [41]

Answer:

25 mL

Explanation:

Step 1: Given data

  • Concentration of the concentrated solution (C₁): 2 M
  • Volume of the concentrated solution (V₁): ?
  • Concentration of the diluted solution (C₂): 0.1 M
  • Volume of the diluted solution (V₂): 0.500 L

Step 2: Calculate the volume of the concentrated NaCl solution

We will use the dilution rule.

C₁ × V₁ = C₂ × V₂

V₁ = C₂ × V₂ / C₁

V₁ = 0.1 M × 0.500 L / 2 M

V₁ = 0.025 L = 25 mL

4 0
3 years ago
Student A performed gravimetric analysis for sulfate in her unknown using the same procedures we did . Results of her three tria
Andre45 [30]

Let us first calculate the accepted value of sulfate using the molar mass of sodium sulfate.

The molar mass of sodium sulfate is 2 Na + S + 4 O = 2 (22.99) + 32.07 + 4 (16)

Molar mass of Sodium sulfate = 142.05

Molar mass of sulfate = S + 4 (O) = 32.07 + 4 (16) = 96.07

% of sulfate in sodium sulfate = (Molar mass of SO4 / Molar mass of Na2SO4) x 100

% of sulfate = (96.07/142.05) x 100

% of sulfate = 67.6%

Theoretical value for % Sulfate is 67.6%

Percent error is calculated as  

Percent Error = \left | \frac{Experimental - Theoretical}{Theoretical} \right |

Let us calculate mean for student A.

Mean for student A = (68.6 + 66.2 + 67.1) / 3 = 201.9/3 = 67.3 %

% error for student A = \left | \frac{67.3 - 67.6}{67.6} \right |

% error for student A = 0.44%

Mean for student B = (66.7 +66.6 + 66.5)/3 = 199.8 /3 = 66.6 %

% error for student B = \left | \frac{66.6 - 67.6}{67.6} \right |  

% error for student B = 1.48%

Accuracy is the closeness of experimental values to the true value. This is defined in terms of absolute and percent errors.

Since percent error for student A is lower, we can say that student A was more accurate.

The precision of the data depends on the closeness of experimental values to each other. We can see that experimental values for student B were close to each other.

Therefore we can say that student B was more precise.


8 0
3 years ago
Which element glows red when electricity flows through it?
TEA [102]
Neon. Neon is a gas that glows red-ish when electricity flows through it in neon signs etc.
7 0
3 years ago
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