3 years ago

When the water level of a stream or river exceeds its natural banks, it has reached its

Chemistry

1 answer:

Vladimir79 [104]3 years ago

7 0

The answer would be flood stage.

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A hydrate of CoCl2 has a mass of 17.40 g before heating. After heating, the mass of the anhydrous compound is found to be 10.27

melisa1 [442]

Mass CoCl2 = 10.27 g
moles CoCl2 = 10.27 g/ 129.839 g/mol=0.07910

mass water = 17.40 - 10.27=7.13 g
moles water = 7.13 / 18.02 g/mol=0.396

0.396/ 0.07910=5

CoCl2 * 5 H2O

moles CaF2 = 85.8 g/ 78.0748 g/mol=1.10
moles Ca = 1.10
mass Ca = 1.10 x 40.078 g/mol=44.1 g
V = 44.1 / 1.55 =28.5 mL

Greetings!!

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3 years ago

What is the volume, in milliliters, occupied by 30.07 g of an object of density equal to

den301095 [7]

Answer:

$\boxed {\tt 20.317567567568 \ mL}$

Explanation:

The density formula is:

$d=\frac{m}{v}$

Let's rearrange the formula for $v$ . the volume. Multiply both sides by $v$ , then divide by $d$ .

$d*v=\frac{m}{v}*v$

$d*v=m$

$\frac{d*v}{d}=\frac{m}{d}$

$v=\frac{m}{d}$

The volume can be found by dividing the mass by the density. The mass of the object is 30.07 grams and the density is 1.48 grams per milliliter.

$m= 30.07 \ g\\d= 1.48 \ g/mL$

$v=\frac{30.07 \ g}{1.48 \ g/mL}$

Divide. Note, when dividing, the grams, or $g$ will cancel out.

$v= \frac{30.07}{1.48 \ mL}$

$v=20.317567567568 \ mL$

The volume of the object is 20.317567567568 milliliters.

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3 years ago

At what temperature, in Kelvin, will a 250 milliliter cylinder containing 0.100 moles of helium gas have a pressure of 2.50 atmo

lozanna [386]

Use the ideal gas formula-----> PV= nRT

P= 2.50 atm
V= 250 mL= 0.250 L
n= 0.100 moles
R= 0.0821 atmxL/molesxK
T= ?

T= PV/nR

T= (2.50 atm x 0.250 L) / (0.100 moles x 0.0821)= 76.1 K

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3 years ago

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According to the periodic table, which of these elements will form an ion with a –2 charge? calcium

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What is the change in the enthalpy of 120 g/s acid heated in a double pipe heat exchanger from 25°C to 100°C, if the average hea

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