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expeople1 [14]
3 years ago
15

What can one say about the image produced by a thin lens that produces a positive magnification?

Physics
1 answer:
Dafna11 [192]3 years ago
5 0

Answer:

The image is virtual and upright

Explanation:

The magnification of a lens can be written as follows:

M=\frac{y'}{y}=-\frac{q}{p}

where

y' is the size of the image

y is the size of the object

q is the location of the image with respect to the lens

p is the location of the object with respect to the lens

In this situation, the magnification is positive. This means that:

- y' (the image) has same sign as y (the object) --> the image is upright (same orientation as the object)

- q has opposite sign to p --> this means that the image is located on the same side as the object, so it is a virtual image

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Answer:

2.9 kg

Explanation:

Given that a 0.775-m3 rigid tank initially contains air whose density is 1.18 kg/m3.

According to the definition of density

Density = mass/volume

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Mass = 1.18 × 0.775

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Given that the tank is connected to a high-pressure supply line through a valve. The valve is opened, and air is allowed to enter the tank until the density in the tank rises to 4.95 kg/m3.

Using the same density formula

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3 years ago
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W= f d,
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3 years ago
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