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expeople1 [14]
3 years ago
15

What can one say about the image produced by a thin lens that produces a positive magnification?

Physics
1 answer:
Dafna11 [192]3 years ago
5 0

Answer:

The image is virtual and upright

Explanation:

The magnification of a lens can be written as follows:

M=\frac{y'}{y}=-\frac{q}{p}

where

y' is the size of the image

y is the size of the object

q is the location of the image with respect to the lens

p is the location of the object with respect to the lens

In this situation, the magnification is positive. This means that:

- y' (the image) has same sign as y (the object) --> the image is upright (same orientation as the object)

- q has opposite sign to p --> this means that the image is located on the same side as the object, so it is a virtual image

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Draw the following vector: 350 N, 30° south of east [1 cm = 50 N]
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The magnitude and the position of the 350 N vector can be represented using arrow pointing out from the South-East of a Cartesian coordinate.

The given parameters:

  • Magnitude of the vector = 350 N
  • Position of the vector = 30⁰ South east

The vector is represented with arrow pointing out from south-east represented in a Cartesian coordinate.

  • The length of the arrow represents the magnitude of the vector which is 350 N.
  • The direction of the arrow indicated by the arrow head represents the position of the vector.
  • The position of the vector is 30 degrees South of East.

Thus, the magnitude and the position of the 350 N vector can be represented using arrow pointing out from the South-East of a Cartesian coordinate.

Learn more about vector representation here: brainly.com/question/14204873

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Please help :( A ray of laser light strikes a glass surface at an angle θa = 22.5° to the normal. What is the angle θb of the re
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Answer:

Explanation:

We shall apply law of refraction which is as follows

sin i / sinr = μ  , where i is angle of incidence , r is angle of refraction and μ is refractive index

here i = θa = 22.5°

r = θb

μ  = 1.77

sin22.5 / sinθb = 1.77

.3826 / sinθb = 1.77

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θb  = 12.5 °.

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On a night when the moon rises at 9 pm, what is its phase?
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Four equal masses m are located at the corners of a square of side L, connected by essentially massless rods. Find the rotationa
Marat540 [252]

Answer:

Moment of Inertia: It is the property of an object that measures, how much an object can resist it's rotational motion.

We have 4 masses at the corner of square of length L. The formula of moment of inertia will be

                                             I = mL^{2}

<u>Finding the Rotational Inertia of this system</u>

<em>(a) </em><em>that coincides with one side (Ia):</em>

The moment of inertia of each of the two sides is

                                            I = mL^{2}

so, both sides will have the moment of inertia equals to

                                            I = 2mL^{2}

<em>(b) </em><em>that bisects two opposite sides (Ib):</em>

The distance of all four masses from the axis=  L/2

so, the moment of inertia of all four masses will be

                                             I =4m(L/2)^{2}

                                              I =4m(L^{2})/4

The final value will be

                                             I = mL^{2}

8 0
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