Answer:
A. 216.36 
B. 96.56 
Explanation:
Let
be the distance in first part.
= velocity × time
= 85 × 
= 49.58 km
Let
be the distance in first part.
= 130 km
Average velocity = 
When second leg of the trip is
A. Toward north
Average velocity =
}{Total time} [/tex]
Average velocity = 
Average velocity =216.36 
B. Toward south
Average velocity =
}{Total time} [/tex]
Average velocity = 
Average velocity =96.56 
With a ruler and a calculator
Answer:
40·919 m
Explanation:
Initial velocity of the arrow = 46 m/s
Angle at which it is thrown from horizontal = 38°
<h3>At the maximum height, the vertical component of velocity will be 0</h3>
Initial velocity in vertical direction = 46 × sin(38) = 28·32 m/s
From the formula
<h3>v² - u² = 2 × a × s</h3>
where
v is the final velocity
u is the initial velocity
a is the acceleration
s is the displacement
Considering the formula in vertical direction and taking upward direction as positive
v = 0
u = 28·32 m/s
a = - g = - 9·8 m/s²
Let s be the maximum height
- 28·32² = - 2 × 9.8 × s
⇒ s = 40·919 m
∴ The arrow will go 40·919 m high