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VLD [36.1K]
2 years ago
14

A jar contains five blue marbles, six red marbles, and four green marbles. What is the probability you will draw a blue marble f

rom this jar?
Mathematics
1 answer:
Anton [14]2 years ago
5 0
Probability=number of specific outcomes/total of all possible outcomes

There are 5 blue marbles and a total of 15 marbles.

So the probability of drawing a blue marble from the jar is:

5/15

1/3
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What’ set of three numbers could be the side lengths of a triangle
Fudgin [204]

3,4,5

idk if this is right these could work but what type of triangle and what are you trying to figure out

3 0
2 years ago
Rewrite 2 thrids × 12 as a single fraction.
____ [38]
24 thirds (24/3) or 8 (simplified)
3 0
2 years ago
Find the inverse of the function.<br> y=x2 + 4x + 4
adoni [48]

Answer: To find the inverse of the function, we need to make x as a function of y and at the final step make a switch between x and y (i.e. make x as y and y as x)

y = x² + 4x + 4  ⇒⇒⇒ factor the quadratic equation

y = (x+2)(x+2)

y = (x+2)²         ⇒⇒⇒ take the square root to both sides

√y = x+2

x = √y - 2         ⇒⇒⇒ x becomes a function of y

final step:

∴ y = √x - 2   ⇒⇒⇒ the inverse of the given function

So, as a conclusion:

f(x) = y = x² + 4x + 4  ⇒⇒⇒ the given function

f⁻¹(x) = y = √x - 2       ⇒⇒⇒ the inverse of the given function

7 0
3 years ago
Apply the distributive property to factor out the greatest common factor.<br> 56<br> +<br> 32<br> =
valentina_108 [34]

Answer:

8 * (7 + 4)

See process below

Step-by-step explanation:

We start by writing each number in PRIME factor form:

56 = 2 * 2 * 2 * 7

32 = 2 * 2 * 2 * 2 * 2

Notice that the factors that are common to BOTH numbers are 2 * 2 * 2 (the product of three factors of 2).Therefore we see that the greatest common factor for the given numbers is : 2 * 2 * 2 = 8

Using this, we can write the two numbers as the product of this common factor (8) times the factors that are left on each:

56 = 8 * 7

32 = 8 * 2 * 2 = 8 * 4

We can then use distributive property to "extract" that common factor (8) from the given addition as shown below:

56 + 32

8 * 7 + 8 * 4

8 * (7 + 4)

8 * (11)

88

4 0
3 years ago
When simplifying 4x^3-10x^2+6x/2x^3+x^2-3x, what are the term(s) that can be cancelled
brilliants [131]

Answer:

x can be cancelled

Step-by-step explanation:

we are given

\frac{4x^3-10x^2+6x}{2x^3+x^2-3x}

Firstly, we will factor numerator and denominator

and then we can factor it

4x^3-10x^2+6x=2x(2x^2-5x+3)

4x^3-10x^2+6x=2x(2x+1)(x-3)

now, we can factor denominator

2x^3+x^2-3x=x(2x^2+x-3)

2x^3+x^2-3x=x(x-1)(2x+3)

now, we can replace it

\frac{4x^3-10x^2+6x}{2x^3+x^2-3x}=\frac{2x(2x+1)(x-3)}{x(x-1)(2x+3)}

we can see that

both terms are having x common

so, x can be cancelled

So,

x can be cancelled

3 0
3 years ago
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