Let the beam is of length L
Now the stress on both the end is same
now we can say that torque on the beam due to two forces must be zero
also we know that stress at both ends are same
Now from two equations we have
solving above equation we have
<em>so the load is placed at distance 0.4L from the end of 12 mm^2 area</em>
Answer:
In 1957 the Soviet union launched Sputnik , the first satellite in space...
<span>In order to answer this question you need to know the specific heat of aluminum and water.
The source below says 0.900 J/g K and 4.186 J/g K respectively.
Let T be the final temperature to be found:
(0.900 J/g K) x (270 g) x (T - (-20))K = (243T + 4860) J gained by the Al
(4.186 J/g K) x (500 g) x (85 - T)K = (177905 - 2093T ) J lost by the coffee
Set the two expressions for heat gained/lost equal to each other:
243T + 4860 = 177905 - 2093T
Solve for T algebraically:
T = 74.1 °C</span>
I assuming they are not going to be very big just small enough for the car to get over the top and not go backwards. The coasting is all the momentum thy have to get over the hill and they don't have a lot of momentum. hope this helps ☺
Sattelites don't need any fuel to stay in orbit. The applicable law is...."objects in motion tend to stay in motion". Having reached orbital velocity, any such object is essentially "falling" around the earth. Since there is no (or at least very little) friction in the vacuum of space, the object does not slow.... It simply continues.
Sattelites in "low" earth orbit do encounter some friction from the very thin upper atmosphere, and they will eventually "decay".
:)
