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inn [45]
3 years ago
6

Write your original hypothesis here?

Physics
1 answer:
Gekata [30.6K]3 years ago
8 0
WAIT.... What are the items?
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The average distance between the earth and the sun is defined as being one
9966 [12]

Answer:

Astronomical Unit (AU). The definition of AU is the distance between the sun and the earth. Hopes this helps!

Explanation:

3 0
4 years ago
A woman standing before a cliff claps her hands, and 2.8s later she hears the echo. How far away is the cliff? The speed of soun
ella [17]

Answer:

480.2 m

Explanation:

The following data were obtained from the question:

Speed of sound (v) = 343 m/s.

Time (t) = 2.8 s

Distance (x) of the cliff =?

The distance of the cliff from the woman can be obtained as follow:

v = 2x /t

343 = 2x /2.8

Cross multiply

2x = 343 × 2.8

2x = 960.4

Divide both side by the coefficient of x i.e 2

x = 960.4/2

x = 480.2 m

Therefore, the cliff is 480.2 m away from the woman.

4 0
3 years ago
In order to determine the coefficients of friction between rubber and various surfaces, a student uses a rubber eraser and an in
Strike441 [17]

Answer:

μs = 0.75

μk = 0.58

Explanation:

From a force diagram:

m*g*sin \theta - Ff=m*a     (1)

N-m*g*cos \theta = 0         (2)

When it starts slipping, friction force is the maximum and acceleration is 0. Replacing these conditions on (1):

m*g*sin \theta - \mu*m*g*cos \theta=0   Solving for μs:

\mu=tan \theta

μs = tan 36.7° = 0.75

When it moves at constant speed, friction force is kinetic friction and acceleration is 0. With these conditions the coefficient is:

μk = tan 30.1° = 0.58

8 0
4 years ago
A potential difference of 3.27 nV is set up across a 2.16 cm length of copper wire that has a radius of 2.33 mm. How much charge
miskamm [114]

Answer:

Charge = 4.9096 x 10⁻⁷ C

Explanation:

First, we find the resistance of the copper wire.

R = ρL/A

where,

R = resistance = ?

ρ = resistivity of copper = 1.69 x 10⁻⁸ Ω.m

L = Length of wire = 2.16 cm = 0.0216 m

A = Cross-sectional area of wire = πr² = π(0.00233 m)² = 1.7 x 10⁻⁵ m²

Therefore,

R = (1.69 x 10⁻⁸ Ω.m)(0.0216 m)/(1.7 x 10⁻⁵ m²)

R = 2.14 x 10⁻⁵ Ω

Now, we find the current from Ohm's Law:

V =IR

I = V/R

I = 3.27 x 10⁻⁹ V/2.14 x 10⁻⁵ Ω

I = 1.52 x 10⁻⁴ A

Now, for the charge:

I = Charge/Time

Charge = (I)(Time)

Charge = (1.52 x 10⁻⁴ A)(3.23 x 10⁻³ s)

<u>Charge = 4.9096 x 10⁻⁷ C</u>

8 0
4 years ago
How can you verify the archimedes principle?​
Ipatiy [6.2K]

Answer:

It is found that W1 - W2 loss in weight of solid when immersed in water is equal to the weight of the water displaced by the body. This verifies Archimedes' principle.

6 0
3 years ago
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