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3 years ago

Which statement about electric force is true?

Physics

2 answers:

salantis [7]3 years ago

7 0

Electric force is typically weaker than gravitation force.

fenix001 [56]3 years ago

7 0

Answer:

You did not leave options to choose but i can give you some statements about electric force

Explanation:

- The electric force is a interaction between two electricaly charged particles (may be positive or negative) or objects.

-The electric force can be attractive or repulsive, depending on the sign of the charges, if both are positive or negative the force will be repulsive and if the charges have different signs it will be attractive.

-The electric force is inversely proportional to the square of the distance between the charges

-The electric force is directly proportional to the value of the charges

-The equation for the electric force it's called the Coulomb's Law and it says:

$Fe= k\frac{Q1*Q2}{R^{2} }$ in the direction of R

where Q1 and Q2 are the values of the electric charges (Coulomb), R is the distance between the charges and k is the dielectric constant or permittivity of the medium, for the void it is $9*10^{9} N*m/C^{2}$ .

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Which of the following are examples of acceleration?

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Answer:

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To test the quality of water sources in her area, Shameka collects five samples from each water source and tests the quality of

xenn [34]

The missing part of the incomplete question is given below:

Which important step of scientific design is Shameka conducting?

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Answer:

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Explanation:

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3 years ago

PLEASE HEELP!!!

Ann [662]

Answer:

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3 years ago

Your grandmother enjoys creating pottery as a hobby. She uses a potter's wheel, which is a stone disk of radius R-0.520 m and ma

Lesechka [4]

Answer:

0.54454

104.00902 N

Explanation:

m = Mass of wheel = 100 kg

r = Radius = 0.52 m

t = Time taken = 6 seconds

$\omega_f$ = Final angular velocity

$\omega_i$ = Initial angular velocity

$\alpha$ = Angular acceleration

Mass of inertia is given by

$I=\dfrac{mr^2}{2}\\\Rightarrow I=\dfrac{100\times 0.52^2}{2}\\\Rightarrow I=13.52\ kgm^2$

Angular acceleration is given by

$\alpha=\dfrac{\tau}{I}\\\Rightarrow \alpha=\dfrac{\mu fr}{I}\\\Rightarrow \alpha=\dfrac{\mu 50\times 0.52}{13.52}$

Equation of rotational motion

$\omega_f=\omega_i+\alpha t\\\Rightarrow \omega_f=\omega_i+\dfrac{\mu (-50)\times 0.52}{13.52}t\\\Rightarrow 0=60\times \dfrac{2\pi}{60}+\dfrac{\mu (-50)\times 0.52}{13.52}\times 6\\\Rightarrow 0=6.28318-11.53846\mu\\\Rightarrow \mu=\dfrac{6.28318}{11.53846}\\\Rightarrow \mu=0.54454$

The coefficient of friction is 0.54454

At r = 0.25 m

$\omega_f=\omega_i+\dfrac{0.54454 (-50)\times 0.52}{13.52}6\\\Rightarrow 0=60\times \dfrac{2\pi}{60}+\dfrac{0.54454 f\times 0.25}{13.52}6\\\Rightarrow 2\pi=0.06041f\\\Rightarrow f=\dfrac{2\pi}{0.06041}\\\Rightarrow f=104.00902\ N$

The force needed to stop the wheel is 104.00902 N

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3 years ago

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