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3 years ago

Which statement about electric force is true?

Physics

2 answers:

salantis [7]3 years ago

7 0

Electric force is typically weaker than gravitation force.

fenix001 [56]3 years ago

7 0

Answer:

You did not leave options to choose but i can give you some statements about electric force

Explanation:

- The electric force is a interaction between two electricaly charged particles (may be positive or negative) or objects.

-The electric force can be attractive or repulsive, depending on the sign of the charges, if both are positive or negative the force will be repulsive and if the charges have different signs it will be attractive.

-The electric force is inversely proportional to the square of the distance between the charges

-The electric force is directly proportional to the value of the charges

-The equation for the electric force it's called the Coulomb's Law and it says:

$Fe= k\frac{Q1*Q2}{R^{2} }$ in the direction of R

where Q1 and Q2 are the values of the electric charges (Coulomb), R is the distance between the charges and k is the dielectric constant or permittivity of the medium, for the void it is $9*10^{9} N*m/C^{2}$ .

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How are electric and magnetic forces the same? How are they different?

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They both have a certain force. They are different because that force is different

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3 years ago

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GalinKa [24]

Answer:

Explanation:

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3 years ago

A car battery seems to be malfunctioning (not providing the proper voltage and current to start your car). While the car is off

Stella [2.4K]

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3 years ago

Two satellites are in circular orbits around a planet that has radius 9.00x10^6 m. One satellite has mass 53.0 kg , orbital radi

Andreas93 [3]

Answer:

The orbital speed of this second satellite is 5195.16 m/s.

Explanation:

Given that,

Orbital radius of first satellite $r_{1}= 8.20\times10^{7}$

Orbital radius of second satellite $r_{2}=7.00\times10^{7}\ m$

Mass of first satellite $m_{1}=53.0\ kg$

Mass of second satellite $m_{2}=54.0\ kg$

Orbital speed of first satellite = 4800 m/s

We need to calculate the orbital speed of this second satellite

Using formula of orbital speed

$v=\sqrt{\dfrac{GM}{r}}$

From this relation,

$v_{1}\propto\dfrac{1}{\sqrt{r}}$

Now, $\dfrac{v_{1}}{v_{2}}=\sqrt{\dfrac{r_{2}}{r_{1}}}$

$v_{2}=v_{1}\times\sqrt{\dfrac{r_{1}}{r_{2}}}$

Put the value into the formula

$v_{2}=4800\times\sqrt{\dfrac{ 8.20\times10^{7}}{7.00\times10^{7}}}$

$v_{2}=5195.16\ m/s$

Hence, The orbital speed of this second satellite is 5195.16 m/s.

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3 years ago

Potential energy becomes kinetic energy when:

Sedbober [7]

Answer:

An object has potential energy (stored energy) when it is not in motion. Once a force has been applied or it begins to move the potential energy changes to kinetic energy (energy of motion).

EXAMPLE: A rock sitting on the edge of a cliff. If the rock falls, the potential energy will be converted to kinetic energy, as the rock will be moving. A stretched elastic string in a longbow.

5 0

2 years ago