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ad-work [718]
3 years ago
10

A spaceship starting from a resting position accelerates at a constant rate of 9.8 m/s. How far will the spaceship travel if its

final speed is 1 percent of the speed of light (300, 000, 000 m/s?)
Physics
1 answer:
Dvinal [7]3 years ago
3 0

300 000 0 squared = 2 x 9.8 distance

KINEMATICS

Uniform or constant motion in a straight line (rectilinear). Speed or velocity constant and/or acceleration constant. If motion is up and down and/or has an up and down component then acceleration omn earth will be g. g is about 10m/s/s.


speed = distance/time

velocity = displacement/time

s=distance ... u=initial speed ... v = final speed ... a = acceleration ... t = time


v=u+at

v^2=u^2+2as

s=ut+1/2at^2

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A few examples:
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3 years ago
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Which of the following is an advantage of asexual reproduction compared to sexual reproduction?
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Question 4 A car of mass 820 kg has a maximum power or 30 kW and moves against a constant resistance of motion to 910 N. Calcula
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7 0
2 years ago
Can someone help me on question 1?
grigory [225]
In question 1, both of your answers are correct, but I don't understand the process you went through in the 'a' part.

R = v/I . That's a correct formula.
But it doesn't help you in this form, because you need to find I
So turn it into a helpful form ... Solve it for I, so it says I=something.

R= v/I

Multiply each side by I : R I = V.

Now divide each side by R: I= V/R .
THERE'S the equation you want.

I = V / R

I = 1.5 / 10 = 0.15 Amp.

That's slightly cleaner, although I don't really understand what you were actually thinking in that part.

But again ... You answered both parts correctly, and your process in b is fine.
6 0
3 years ago
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