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Marrrta [24]
3 years ago
8

Select the GCF of these numbers.

Mathematics
2 answers:
kiruha [24]3 years ago
8 0
ANSWER

{2}^{3}  \times 5



EXPLANATION


We want to find the greatest common factor of

{2}^{5}  \times 5 \times 11

and

{2}^{3}  \times  {5}^{2}  \times7

To find the greatest common factor, we need to identify the factors that are common to both numbers.

Then we pick the factors with the lowest degree and multiply them


This will give us,


{2}^{3}  \times 5

The correct answer is D.
Marysya12 [62]3 years ago
4 0
The Greatest Common Factor (GCF) of 25, 5, 11 and 23, 52, 7 is 1, same with 22,3 and 23, 5 and 13, 193, 232.
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cos (x)  \leq \frac{sin (x)}{x}  \leq 1

Apply limit as x->0
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Your answer would be A)

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I did it wrong the first time
kvv77 [185]

Answer:

4.6

Step-by-step explanation:

For this question, we need the opposite side and have the opposite

with that said, out of SOH, CAH, TOA it's fastest to use TOA

tan(75)=17/x

17/(tan(75))=x

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3 years ago
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Arthur has decided to start saving for a new computer. His money is currently in a piggy bank at home, modeled by the function s
Leya [2.2K]

Two or more independent functions (say f(x) and g(x)) can be combined to generate a new function (say g(x)) using any of the following approach.

h(x) = f(x) + g(x)         h(x) = f(x) - g(x)

h(x) = \frac{f(x)}{g(x)}                   h(x) = f(g(x))

And many more.

The approach or formula to use depends on the question.

In this case, the combined function is:

f(x) = 75+ 10x

The savings function is given as

s(x) = 85

The allowance function is given as:

a(x) = 10(x - 1)

The new function that combined his savings and his allowances is calculated as:

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Substitute values for s(x) and a(x)

f(x) = 85 + 10(x - 1)

Open bracket

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Read more about functions at:

brainly.com/question/15458447

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Let's say we wanted to subtract these measurements.

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45.367 - 43.43 = 1.937

But let's take the idea that measurements were rounded to that last decimal place.  

So 45.367 might be as small as 45.3665 or as large as 45.3675.

Similarly 43.43 might be as small as 43.425 or as large as 43.435.

So our difference may be as large as

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If we express our answer as  1.937 that means we're saying the true measurement is between 1.9365 and 1.9375.  Since we determined our true measurement was between 1.9313 and 1.9425, the measurement with more digits overestimates the accuracy.

The usual rule is to when we add or subtract to express the result to the accuracy our least accurate measurement, here two decimal places.

We get 1.94 so an imputed range between 1.935 and 1.945.  Our actual range doesn't exactly line up with this, so we're only approximating the error, but the approximate inaccuracy is maintained.


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