B.
4 goes into 75 18 times and has a remainder of 3, so it’s 18 3/4
Answer:
= −31/4
(Decimal: -7.75)
Step-by-step explanation:
<h2>
Answer:</h2>

<h2>
Step-by-step explanation:</h2>
As the question states,
John's brother has Galactosemia which states that his parents were both the carriers.
Therefore, the chances for the John to have the disease is = 2/3
Now,
Martha's great-grandmother also had the disease that means her children definitely carried the disease means probability of 1.
Now, one of those children married with a person.
So,
Probability for the child to have disease will be = 1/2
Now, again the child's child (Martha) probability for having the disease is = 1/2.
Therefore,
<u>The total probability for Martha's first child to be diagnosed with Galactosemia will be,</u>

(Here, we assumed that the child has the disease therefore, the probability was taken to be = 1/4.)
<em><u>Hence, the probability for the first child to have Galactosemia is
</u></em>
X^2 + yz......x = 5, y = -3, z = 2
now we sub
5^2 + (-3)(2) =
25 + (-6) =
25 - 6 =
19