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3 years ago

Which of the following will result in a chemical change?

Chemistry

2 answers:

Alinara [238K]3 years ago

5 0

C burning coal in a furnace

Galina-37 [17]3 years ago

3 0

The answer is C. I just finished the test.

Bliss Up

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For the reaction: N2O5(g) \longrightarrow&longrightarrow; 2NO2(g) + 1/2O2(g)

ivanzaharov [21]

The given equation from the problem above is already balance,
N2O5 ---> 2NO2 + 0.5O2
Since, in every mole of N2O5 consumed, 2 moles of NO2 are formed, we can answer the problem by multiplying the given rate, 7.81 mol/L.s with the ratio.
(7.81 mol/L.s) x (2 moles NO2 formed/ 1 mole of N2O5 consumed)
= 15.62 mol/L.s
The answer is the rate of formation of NO2 is approximately 15.62 mol/L.s.

5 0

3 years ago

Heating by direct contact between particles is called ____________

nataly862011 [7]

Answer:

conduction

Explanation:

Conduction is the transfer of heat between substances that are in direct contact with each other. ... Conduction occurs when a substance is heated, particles will gain more energy, and vibrate more. These molecules then bump into nearby particles and transfer some of their energy to them.

3 0

2 years ago

I am fueled by the warm water of the ocean. As the warm water evaporates it rises until there is an enormous amount of heated mo

DedPeter [7]

It's a definitely a hurricane.

8 0

3 years ago

How to find limiting reagent

Nookie1986 [14]

The reagent which limits the reaction is called limiting reagents.

____

For example:- N2+3H2gives 2NH3.so here nitrogen limits the reaction.

3 0

3 years ago

Read 2 more answers

How many milliliters of a 0.285 M HCl solution are needed to neutralize 249 mL of a 0.0443 M Ba(OH)2 solution?

meriva

Answer:

$\large \boxed{\text{77.4 mL}}$

Explanation:

Ba(OH)₂ + 2HCl ⟶ BaCl₂ + H₂O

V/mL: 249

c/mol·L⁻¹: 0.0443 0.285

1. Calculate the moles of Ba(OH)₂

$\text{Moles of Ba(OH)$_{2}$} = \text{0.249 L Ba(OH)}_{2} \times \dfrac{\text{0.0443 mol Ba(OH)}_{2}}{\text{1 L Ba(OH)$_{2}$}} = \text{0.011 03 mol Ba(OH)}_{2}$

2. Calculate the moles of HCl

The molar ratio is 2 mol HCl:1 mol Ba(OH)₂

$\text{Moles of HCl} = \text{0.011 03 mol Ba(OH)}_{2} \times \dfrac{\text{2 mol HCl}}{\text{1 mol Ba(OH)}_{2}} = \text{0.022 06 mol HCl}$

3. Calculate the volume of HCl

$V_{\text{HCl}} = \text{0.022 06 mol HCl} \times \dfrac{\text{1 L HCl}}{\text{0.285 mol HCl}} = \text{0.0774 L HCl} = \textbf{77.4 mL HCl}\\\\\text{You must add $\large \boxed{\textbf{77.4 mL}}$ of HCl.}$

8 0

3 years ago