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3 years ago

A cable television provider offers six

Mathematics

1 answer:

lubasha [3.4K]3 years ago

7 0

Answer:

24 stations

Step-by-step explanation:

we know that

six stations represent 25% of the stations offered

using a proportion

Find out how many stations represent a percentage of 100%

$\frac{6}{25\%}=\frac{x}{100\%}\\\\x=6(100)/25\\\\x=24\ stations$

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You have 19 digs for your current volleyball season. There are 5 games left in the season. You want to break your previous recor

Charra [1.4K]

Answer:We must get more than 7 digs in the remaining 5 games to break record of 26.

Step-by-step explanation:

Given situation:- Let x represents the number of digs which we must get in the remaining 5 games to break your record ,and we have 19 digs for our current volleyball season.

To break previous record of 26 digs in a season, we have to get more than 26 i.e. 19 digs added to x must be greater than 26

⇒x+19 ≥ 26

⇒x≥26-19⇒x≥7

Therefore,we must get more than 7 digs in the remaining 5 games to break record of 26.

4 0

3 years ago

45-2x(15-3) I need help finding out the answer to this problem because the answer I got I think it is wrong

gizmo_the_mogwai [7]

45 - 2*(12)
45 - 24
21

Hope this helps!

6 0

3 years ago

A right triangle has a perimeter of 24 cm and a hypotenuse of 10 cm. Find the length of the other two sides.

jekas [21]

Answer:

One of the sides is 6 cm and the other is 8 cm

Step-by-step explanation:

Let's call the unknown sides a and b. From the perimeter information (24 cm) we have:

a + b + hypotenuse = 24

a + b + 10 = 24

a + b = 14

b = 14 - a

So now we can right the Pythagorean theorem as follows:

$a^2 + b^2 = hypotenuse^2\\a^2 + (14-a)^2=10^2\\a^2+ 14^2-28\,a+a^2=100\\2\,a^2-28\,a +96=0\\2\,(a^2-14\,a+48)=0\\2\,(a^2-6\,a-8\,a+48)=0\\2(a\,(a-6)-8\,(a-6))=0\\2\,(a-6)\,(a-8)=0$

and from this expression in factor form to be zero a must be 6 or a must be 8.

Therefore the solutions are a = 6 (and therefore b = 14 - 6 = 8)

or a = 8 (and therefore b = 14 - 8 = 6)

7 0

3 years ago

Read 2 more answers

Click on the graphic to select the figure that would make the following a reflection in line k

Roman55 [17]

I remember answering the same question, but you didn't attach any photos. But I remember that the answer is the first one.

I hope I helped. Stay safe and God bless!

- Eli <3

6 0

3 years ago

I need #14 done by tomorrow around 9-10:00. Thank you so much if you do. God bless you :3

Vinvika [58]

Answer:

A) $\frac{1}{5}$

B) - 5

C) Not Possible

D) 5

E) $\frac{-1}{5}$

Step-by-step explanation:

All integers are rational numbers. But not all rational numbers are integers.

All whole numbers are integers. But not all integers are whole numbers.

I am a rational number but not an integer. Located on the right of 0.

This means that it should be a positive number. Since, it is a rational number but not an integer, it should be of the form $\frac{p}{q}$ .

From, the options $\frac{1}{5}$ would fit this description.

I am a rational number and an integer but not a whole number.

This means that it should be a negative integer. Since, all positive integers and zero would be whole numbers. From the options, the answer would be -5.

I am a whole number but not an integer.

This is clearly not possible because all whole numbers are a subset of integers.

I am a rational number, a whole number and an integer.

This means it is a positive integer. 5 would fit this description.

I am a rational number but not an integer; located on the left side of 0.

This means it is a negative number. $-\frac{1}{5}$ should be the answer.

3 0

3 years ago