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Zigmanuir [339]
4 years ago
12

Machine A working alone can complete a job in 3 1/2 hours. Machine B working alone can do the same job in 4 2/3 hours. How long

will it take both machines working together at their respective constant rates to complete the job?A. 1 hr 10 minB. 2hrC. 4hr 5 minD. 7hrE. 8 hr 10 min
Mathematics
1 answer:
SIZIF [17.4K]4 years ago
5 0

Answer:

B) 2 hours

Step-by-step explanation:

If machine  A complete a job in 3 1/2 hours or 7/2 of an hour

means that in one hour finished 1÷ 7/2     or  2/7

If machine  B complete a job in 4 2/3 hours or  14/3 of an hour

means that in one hour finished 1÷ 14/3    or  3/14 of an hour

Then the two machines working together in one hour will make

2/7 + 3/14    =  (4 + 3)/ 14

or   7/14   = 1/2

half of the job. Therefore these two machines working together will take two hours

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5 0
3 years ago
Please give answers for all
aivan3 [116]

Answer:

Step-by-step explanation:

5x+20 = 0

5X= -20

X= -20/5 = -4

8(4n+3) = 32n+24 =0

32n = -24

n = -24/32 = -3/4

12n-6=0

12n =6

n = 6/12 = 1/2

9(2x+9)

18x+81 =0

18x= -81

x= -81/18 = -9/2= -4.5

36+9y=0

36=-9y

36/-9 = y = -4

7(n-3) = 0

7n-21=0

7n = 21

n = 21/7

n=3

21+15a = 0

21= -15a

a= 21/-15 = 7/-5 = -1.4

32x-12x=0

20x=0

x=0/20 = 0

n-4-9=0

n-13=0

n=13

-3x-9+15x=0

-3x+15x-9 =0

12x-9=0

12x=9

x=9/12 = 3/4 = 0.75

-16N-14N=0

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n=0/-30 =0

-10-90x-6x-10x²-2

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-12-96x-10x²

10x²+96x+12

x= -b±√b²-4(a)(c)/2a

   {-96±√96²-4(10)(12)}/2(10)

{-96±√(9216-480)}/20

-96±√8736/20

-96±(93.4665715644)/20

-96+93.4665715644/20        -96-93.4665715644/20

-2.5334284356/20                 -189.466571564/20

-0.12667142178≅ -0.13             -9.4733285782≅ -9.47

-0.13                                                -9.47

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-45n = 45

n = 45/-45 =-1

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n = -18/16 = -9/8 = -1.125

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3-21n=0

3=21n

3/21=n = 1/7

3n-(2n-8)

3n-2n+8=0

n+8=0

n=-8

5 0
3 years ago
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