At which root does the graph of f(x) = (x – 5)3(x + 2)2 touch the x axis?
2 answers:
Answer:
x=5 and x=-2
Step-by-step explanation:
Knowing that a root is a "x" value where f(x)=0, and consequently the graphic goes through the absise (x axis). We have that when:
f(5)=(5-5)3(5+2)2 =0
and
f(-2)= (-2+5)3(-2+2)2 =0
Then, x=5 and x= -2 are function's roots and the graph touchs the x axis in two "x" values.
All of them
the roots of thhe equaiton are the x intercept
they would be at x=5 and x=-2
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