<h3>CHEMISTRY</h3>
What is the most basic aromatic amine’s common name?
a) Benzenamine
b) Benzylamine
c) Aniline
d) Aminobenzene
#BRAINLYEVERYDAY
The water vapor will begin to contract. The particles will begin to bond with each other to seek heat so they're contracting.
Answer:
![[H_3O^+]=4.7x10^{-3}M](https://tex.z-dn.net/?f=%5BH_3O%5E%2B%5D%3D4.7x10%5E%7B-3%7DM)
Explanation:
Hello there!
In this case, since the ionization of benzoic acid is:
![HC_7H_3O_2+H_2O\rightleftharpoons C_7H_3O_2^-+H_3O^+](https://tex.z-dn.net/?f=HC_7H_3O_2%2BH_2O%5Crightleftharpoons%20C_7H_3O_2%5E-%2BH_3O%5E%2B)
Whereas the corresponding equilibrium expression is:
![Ka=\frac{[C_7H_3O_2^-][H_3O^+]}{[HC_7H_3O_2]}](https://tex.z-dn.net/?f=Ka%3D%5Cfrac%7B%5BC_7H_3O_2%5E-%5D%5BH_3O%5E%2B%5D%7D%7B%5BHC_7H_3O_2%5D%7D)
Now, we insert the acidic equilibrium constant and the reaction extent x, to write:
![6.3x10^{-5}=\frac{x^2}{0.35M}](https://tex.z-dn.net/?f=6.3x10%5E%7B-5%7D%3D%5Cfrac%7Bx%5E2%7D%7B0.35M%7D)
Thus, by solving for x, we obtain:
![x=\sqrt{6.3x10^{-5}*0.35}\\\\x=4.7x10^{-3}M](https://tex.z-dn.net/?f=x%3D%5Csqrt%7B6.3x10%5E%7B-5%7D%2A0.35%7D%5C%5C%5C%5Cx%3D4.7x10%5E%7B-3%7DM)
Which is also:
![x=4.7x10^{-3}M](https://tex.z-dn.net/?f=x%3D4.7x10%5E%7B-3%7DM)
Best regards!
Answer:
0.11645 moles
Explanation:
moles=n
M is molar mass of substance
m is in grams
n=m/M
So, 7.40/63.546 = 0.11645
0.116(rounded to sig figs)