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vodomira [7]
4 years ago
11

The picture below shows a mixture that was stirred 3 minutes ago.

Chemistry
2 answers:
zimovet [89]4 years ago
5 0
This compound should be classified as a suspension fluid. This happens when a fluid is denser than another fluid.
Galina-37 [17]4 years ago
4 0
When the <span>particles</span> settle it is a suspension. The answer is D
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When balancing a chemical equation, what are the large numbers that we adjust?
Nata [24]

Answer:

Coefficients

Explanation:

Chemical equations are first written as a skeleton equation, which includes how many atoms each element and compound has. Skeleton equations are not 'balanced' because the number of atoms of each element on the left side (reactants) is not equal to the right side (products).

To balance a chemical equation, you can write coefficients in front of single elements and compounds. The coefficient multiplies with each single element and with each element in the compound.

For example, in this skeleton equation:

H₂ + Cl₂     =>       HCl

Reactants:          Products:

2 hydrogen         1 hydrogen

2 chlorine            1 chlorine

Write the coefficient 2 in the products.

H₂ + Cl₂     =>       2HCl

Now both reactant and product sides have 2 chlorine and 2 hydrogen, so the equation is balanced.

6 0
4 years ago
HELP HELP HELP HELP!!!
Paha777 [63]

Answer:

The top right box

Explanation:

during a lunar eclipse, the earth is in between the sun and moon

8 0
3 years ago
Read 2 more answers
5.080 x 1016 molecules of hydrogen to moles
lawyer [7]
For this problem, to determine the number of moles given the number of molecules, we use the Avogadro's number. This is an empirical value that relates the number of particles (e.g. atoms, molecules, sub-particles) in one mole of any substance. The value is 6.022×10²³ molecules/mol.

5.080×10¹⁶ molecules * 1 mol/6.022×10²³ molecules = <em>8.436×10⁻⁸ moles of hydrogen</em>
3 0
3 years ago
A balloon originally had a volume of 4.39 L at 44C and a pressure of 729 torr  to what temperature must the balloon be cooled
VMariaS [17]

The new temperature : 11.56 °C

<h3>Further explanation </h3>

Boyle's law and Gay Lussac's law  

\tt \dfrac{P_1.V_1}{T_1}=\dfrac{P_2.V_2}{T_2}

P1 = initial gas pressure (N/m² or Pa)  

V1 = initial gas volume (m³)  

P2 = final gas pressure  

V2 = final gas volume

T1 = initial gas temperature (K)  

T2 = final gas temperature  

V₁=4.39 L

T₁=44+273=317 K

P₁ = 729 torr = 0,959211 atm

V₂=3.78 L

P₂= 1 atm

\tt \dfrac{0.959211\times 4.39}{317}=\dfrac{1\times 3.78}{T_2}\\\\T_2=\dfrac{1\times 3.78\times 317}{0.959211\times 4.39}\\\\T_2=284.559~K=11.56~C

3 0
3 years ago
How many grams of ethane gas (C2H6) are in a 12.7 liter sample at 1.6 atmospheres and 24°C? Show all work used to solve this pro
dexar [7]

n = PV/RT

p = 1.6 atm

v = 12.7L

R = 0.0821

T = 24°C which is equivalent to 297.15 degrees k

n = (16 × 12.7) / (0.0821 × 297.15)

n = 20.32 / 24.39

n = 0.83 mol

C = 12.90

H = 1.0079

C2 = 12.010 × 2 = 24.02

H6 = 1.0079 × 6 = 6.0474

C2H6 = 30.0674

Ethane times n which is 30.0674 × 0.83mol

= 24.95 grams of C2H6. Which is Ethane.

4 0
4 years ago
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