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svetoff [14.1K]
3 years ago
13

Select the message that most accurately fits the passage.

Chemistry
2 answers:
Xelga [282]3 years ago
7 0

Answer:

B. Black holes are incredibly powerful cosmic forces.

Explanation:

the passage support this.

Kaylis [27]3 years ago
4 0

Answer:The answer is B

Explanation: I just take I’m sure bc I just got it right

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What is Mars colonization?
serious [3.7K]

Answer:The colonization of Mars has received interest from public space agencies and private corporations and has received extensive hypothetical treatment in science fiction writing, film, and art.

Explanation:

3 0
2 years ago
The ka of hypochlorous acid (hclo) is 3.0 x 10-8 at . what is the % ionization of hypochlorous acid in a 0.015 m aqueous solutio
Ahat [919]

Answer is: the % ionization of hypochlorous acid is 0.14.

Balanced chemical reaction (dissociation) of an aqueous solution of hypochlorous acid:

HClO(aq) ⇄ H⁺(aq) + ClO⁻(aq).

Ka = [H⁺] · [ClO⁻] / [HClO].

[H⁺] is equilibrium concentration of hydrogen cations or protons.

[ClO⁻] is equilibrium concentration of hypochlorite anions.

[HClO] is equilibrium concentration  of hypochlorous acid.

Ka is the acid dissociation constant.

Ka(HClO) = 3.0·10⁻⁸.

c(HClO) = 0.015 M.

Ka(HClO) = α² · c(HClO).

α = √(3.0·10⁻⁸ ÷ 0.015).

α = 0.0014 · 100% = 0.14%.

5 0
3 years ago
A chemical reaction that removes electrons from an atom is called a(n) ________ reaction.
ch4aika [34]
A chemical reaction that removes electrons from an atom is called "O<span>xidation".
The term came from late 18th century from French.
When the electrons are removed from an atom it increase its valence.</span>
3 0
3 years ago
What is FeBr3 compound name?
inessss [21]
Iron bromide. Iron bromide (FeBr3)
3 0
3 years ago
Read 2 more answers
While doing a lab a student found the density of a piece of pure aluminum to be 2.85 g/cm3 the accepted value for the density of
____ [38]

Answer:

THE PERCENT ERROR IS 5.55 %

Explanation:

To calculate the percent error, we use the formula:

Percent error = Found value - accepted value / accepted value * 100

Found value = 2.85 g/cm3

Accepted value = 2.70 g/cm3

Solving for the percent error, we have:

Percent error = 2.85 g/cm3 - 2.70 g/cm3 / 2.70 g/cm3 * 100

Percent error = 0.15 / 2.70 * 100

Percent error = 0.05555 * 100

Percent error = 5.55 %

In conclusion, the percent error is 5.55 %

3 0
3 years ago
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