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2 years ago

Hydrocarbons having the same formula but variations in structure are called isomers.

Chemistry

1 answer:

zhannawk [14.2K]2 years ago

5 0

Answer:The given statement is true.

Explanation:

Isomers are defined as two or more compounds with same structural formula but different arrangement of atom and chemical properties.

For example: Butane, 2-methyl propane are isomers with structural formula $C_4H_{10}$ , acetone and propanal both isomers to each other with same structural formula of $C_3H_6O$ .

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Which product is used on the natural nail prior to product application to assist in adhesion and serves to chemically bond the e

ira [324]

The product that is used on the natural nail prior to application to assist in adhesion and serves to chemically bond the enhancement product to the natural nail is known as nail primer.

<h3>What is a nail primer?</h3>

A nail primer is a chemical agent used in esthetic centers before applying a colored polish to the nails and serves as an adhesive product.

The nail primers are also very useful for improving the cleaning efficiency of the product before its application.

Nail care products include different types of chemical formulations such as, for example, creams that reinvigorate the cuticle.

In conclusion, the chemical formulation employed on the natural nail that is capable of enhancing and also assisting adhesion is called the nail primer.

Learn more about nail esthetic products here:

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8 0

1 year ago

The total volume of seawater is 1.5 x 1021L .Assume that seawater contains 3.1 percent sodium chloride by mass and that its dens

son4ous [18]

Answer:

Mass in kg = 4.7*10^19 kg

Mass in tons = 5.2*10^16 tons

Explanation:

<u>Given:</u>

Total volume of sea water = 1.5*10^21 L

Mass % NaCl in seawater = 3.1%

Density of seawater = 1.03 g/ml

<u>To determine:</u>

Total mass of NaCl in kg and in tons

<u>Calculation:</u>

Unit conversion:

1 L = 1000 ml

The volume of seawater in ml is:

$=\frac{1.5*10^{21}L*1000ml }{1L} =1.5*10^{24} ml$

$Mass\ seawater = Density*volume = 1.03g/ml*1.5*10^{24} ml=1.5*10^{24}g$

$Mass\ NaCl\ in\ seawater = \frac{3.1}{100}*1.5*10^{24} g=4.7*10^{22} g$

To convert mass from g to Kg:

1000 g = 1 kg

$Mass\ seawater(kg) = \frac{4.7*10^{22}g*1kg }{1000g} =4.7*10^{19} kg$

To convert mass from g to tons:

1 ton = 9.072*10^6 g

$Mass\ seawater(tons) = \frac{4.7*10^{22}g*1ton }{9.072*10^{6}g } =5.2*10^{16} tons$

5 0

2 years ago

Binigyan ang isang liham ng pasasalamat at gagawin ko rin siya ng kabutihan sa ibang pagkakataon

anzhelika [568]

Answer:

what language do you speak?

8 0

1 year ago

Which of the following actions will lead to an increase in pressure?

MatroZZZ [7]

By decreasing n we can increase presure because decrease in n will shift equilibrium to either forward or reverse direction

3 0

2 years ago

How many sulfur atoms are generated when 9.42 moles of H2S react according to the following equation: 2H2S+SO2→3S+2H2O

8_murik_8 [283]

Answer:

A) 8.51 × 10²⁴

Explanation:

1. Gather all the information

2H₂S + SO₂ ⟶ 3S + 2H₂O

n/mol: 9.42

2. Calculate the moles of S atoms

The molar ratio is 3 mol S:2 mol H₂S

$\text{Moles of S} = \text{9.42 mol H$_{2}$S} \times \dfrac{\text{3 mol S }}{\text{2 mol H$_{2}$S }} = \text{14.13 mol S}$

3. Calculate the atoms of S

$\text{Atoms of S } = \text{14.13 mol S} \times \dfrac{6.022 \times 10^{23}\text{ S atoms}}{\text{1 mol S}} = \mathbf{8.51 \times 10^{24}}\textbf{ S atoms}$

6 0

2 years ago

Read 2 more answers