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Aleksandr-060686 [28]
3 years ago
14

What is the arrow pointing to?

Physics
1 answer:
e-lub [12.9K]3 years ago
7 0

Answer: A. Spine

Hope this helps.

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Mr. Fineman rolls a tennis ball off his desk. If his desk is 1 m tall, and the tennis ball is rolling off of his desk at a speed
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Answer:

The URL you requested has been blocked

The page you requested has been blocked because it contains a banned word.

URL: https://www.scribd.com/document/359448624/Solutions-Manual-pdf

User name: 22035460

Group name: HS-Students

Explanation:i really tryed but my school blocks us from learning but heres the link https://www.scribd.com/document/359448624/Solutions-Manual-pdf

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3 years ago
What is the acceleration of a 59 kg object pushed with a force of 500 Newton's ?
Igoryamba

Answer:

a=500/50=10 m/s^2

Explanation:

f=m•a     a=f/m

a=500/50= 10 m/s^2

4 0
2 years ago
A car travels a distance of 98 meters in 10 seconds. What is the average speed of the car?
stira [4]

Answer:

C

Explanation:

4 0
3 years ago
Read 2 more answers
Is this a testable question?
faltersainse [42]
This is a non testable question because it cannot be answered by doing an experiment. But it could be modified for example Dogs are more obedient then cats.
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3 years ago
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A firecracker in a coconut blows the coconut into three pieces. Twopieces of equal mass fly off south and west, perpendicular to
loris [4]

Answer:

V = 13m/s

North-East (i.e. 45 degree from North)

Explanation:

This question deals with the idea of momentum.

Since the directions of a compass are fixed, we can take south as horizontal and west as vertical. Since both pieces of coconut are of equal mass, then the resultant of the two pieces would be in between South and West and the third piece would be opposite this direction and be in the North-East (i.e. 45 degree from North) direction

To find the speed of the third piece, we first find the speed on the two pieces of the coconut in terms of V_{x} (horizontal component of velocity) and V_{y} (vertical component of velocity)

We have

V_{y} = Velocity in South direction = 18m/s

m_{y} = Mass of piece in South direction = m

V_{x} = Velocity in West direction = 18m/s

m_{x} = Mass of piece in West direction = m

V_{ry} = Velocity of Third Piece in North direction = unknown

V_{rx} = Velocity of Third Piece in East direction = unknown

m = Mass of third piece = 2m

mV_{ry}  = m_{y} V_{y} \\ 2mV_{ry}  = m18\\ V_{ry} = 9

mV_{rx}  = m_{x} V_{x} \\ 2mV_{rx}  = m18\\ V_{rx} = 9

Since we now know the horizontal and vertical component of the velocity of the third piece of coconut we find the resultant velocity. Since we know the direction is North-East, we can imagine a right angled triangle with base of 9 and height 9 and the hypotenuse equal to the resultant velocity .

We can simply apply the Pythagoras theorem and find the hypotenuse

Hypotenuse^{2}  = Height^{2}  + Base^{2} \\ V_{3}^2  = 9^{2} + 9^{2} \\ V = 12.728 m/s

V = 13m/s

6 0
3 years ago
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