First do 1.6 m (how far he jumps) 9.8 m/s (what gravity is measured at) then times 2
= 31.36
Sq root = 5.6
Let current be I, charge be Q and time be t.
Here we are provided with,
I = 0.72A
t = 4s / 60s / 180s / 7s / 0.5s
We know,
I = Q/t
Case I
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When, t = 4s
0.72 = Q/4
Q = 0.72 * 4 = 2.88C
Case II
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When, t = 60s
0.72 = Q/60
Q = 0.72 * 60 = 43.2C
Case III
-----------
When, t = 180s
0.72 = Q/180
Q = 0.72 * 180 = 129.6C
Case IV
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When, t = 7s
0.72 = Q/7
Q = 0.72 * 7 = 5.04C
Case V
----------
When, t = 0.5s
0.72 = Q/0.5
Q = 0.72 * 0.5 = 0.36C
Answer:
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Explanation:
Answer:
1. The current will drop to half of its original value.
Explanation:
The problem can be solved by using Ohm's law:
where
V is the voltage across the circuit
R is the resistance of the circuit
I is the current
We can rewrite it as
In this problem, we have:
- the resistance of the circuit remains the same: R' = R
- the voltage is decreased to half of its original value:
So, the new current will be
so, the current will drop to half of its original value.