All categories

4 years ago

What is the area of rectangle ABCD given the information below?

Mathematics

1 answer:

SashulF [63]4 years ago

7 0

Answer: Area is 1840units²

Step-by-step explanation:

From the given information,

Firstly, area of a rectangle is given as

A = l × b ie, length multiply by the breadth.

One of the side of the rectangle is known , AD = 16 , now to calculate the other side, we need some calculations.Since FE = 23 and

FD = DE ,,therefore,

DE = 23/2.

From the information, DE = 1/10 of DC. We now find DC the required side for finding the area of the rectangle by simple equation. Since DE = 23/2 , the equation now looks like this to get DC

23/2 = DC/10. Now , solving this

2DC = 23 × 10

2DC = 230

DC = 230/2

= 115.

Now the area of the rectangle will be

A = 16 × 115

= 1840units²

You might be interested in

A certain railway company claims that its trains run late 5 minutes on the average. The actual times (minutes) that 10 randomly

iragen [17]

Answer:

Option C) We would reject the claim that the trains run late an average of 5 minutes and conclude that they run late an average of more than 5 minutes since the 99% confidence interval exceeds 5.

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = 5 minutes

Sample mean, $\bar{x}$ = 9.130 minutes

Sample size, n = 10

Alpha, α = 0.01

Sample standard deviation, s = 1.4 minutes

First, we design the null and the alternate hypothesis

$H_{0}: \mu = 5\text{ minutes}\\H_A: \mu \neq 5\text{ minutes}$

We have to construct 99% confidence interval.

99% Confidence interval:

$\bar{x} \pm t_{critical}\displaystyle\frac{s}{\sqrt{n}}$

Putting the values, we get,

$t_{critical}\text{ at degree of freedom 9 and}~\alpha_{0.01} = \pm 3.249$

$9.130 \pm 3.249(\dfrac{1.4}{\sqrt{10}} ) = 9.130 \pm 1.4383 = (7.6917,10.5683)$

99% Confidence interval: (7.6917,10.5683)

Since the population mean does not lie in he calculated confidence interval, thus, we fail to accept the null hypothesis and accept the alternate hypothesis.

Option C) We would reject the claim that the trains run late an average of 5 minutes and conclude that they run late an average of more than 5 minutes since the 99% confidence interval exceeds 5.

6 0

3 years ago

How many solutions would there be for the following systems of equations <br>y=3x-5<br>6x-2y=10

Ann [662]

Answer:

So the solution would be (1,-2). Remember you can always validate that the solution is correct by plugging it into both equations. But this is the same as the first equation, y=3x-5. Since they are the SAME line they will have infinite solutions.

Step-by-step explanation:

6 0

3 years ago

The length of Jeff Koon's sculpture is 4 feet more than the width. If the length of the sculpture is 8 feet, what is the area of

Mrrafil [7]

(8+4)x8= 96 feet squared

(There is no little 2 to put in so I just wrote squared)

3 0

3 years ago

A student purchases school supplies at a store where the sale tax is 7%. The pre-tax price of the supplies is $48. What is the t

Alenkasestr [34]

Solution: We are given:

Sales tax $=7\%$