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sergiy2304 [10]
2 years ago
13

Determine the number of molecules present in 1.53 mol of carbon monoxide

Chemistry
1 answer:
ASHA 777 [7]2 years ago
8 0

Answer:

hi

Explanation:

this is my first time on this app so what do i do

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If you have 3.0 moles of argon gas at STP, how much volume will the argon take up?
Anestetic [448]
If you have 3.0 moles of argon gas at STP u would take up 2.5 volume
3 0
3 years ago
a 1.912 g samplw of calcium chloride is decomposed and found to contain 0.690 g of Ca and 1.222 g of Cl. Calculate the mass perc
adoni [48]

Answer:

36.09% is the mass percent composition of calcium in calcium chloride

Explanation:

Mass percent is defined as one hundred times the ratio between the mass of a compound (In this case, Calcium), and the total mass of the sample:

<em>Mass Percent = Mass compound / Total mass of the sample × 100</em>

<em />

Computing the values of the problem:

Mass Percent = 0.690g / 1.912g * 100

Mass percent =

<h3>36.09% is the mass percent composition of calcium in calcium chloride</h3>
8 0
2 years ago
What is the volume of an object with a density of 2.6 g/cm³ and a mass of 30.5g?
inessss [21]

Answer:

The answer is

<h2>11.73 mL</h2>

Explanation:

The volume of a substance when given the density and mass can be found by using the formula

volume =  \frac{mass}{density}

From the question

mass of object = 30.5 g

Density = 2.6 g/cm³

The volume is

volume =  \frac{30.5}{2.6}  \\  = 11.7307692...

We have the final answer as

<h3>11.73 mL</h3>

Hope this helps you

5 0
2 years ago
Force = 2.32 N<br> Acceleration = 0.19 m/s2<br> Mass= ?
Mkey [24]

mass = 12.2 kg

Explanation:

To find the mass we use the following formula (Newton's Second Law of Motion):

force = mass × acceleration

mass = force / acceleration

mass = 2.32 N / 0.19 m/s²

mass = 12.2 kg

Learn more about:

Newton's Second Law of Motion

brainly.com/question/834262

#learnwithBrainly

3 0
2 years ago
Relative formula mass of glucose? (C6H12O6)
Rom4ik [11]

To find the mass of glucose, you must multiply the atomic weight of each of the elements in the molecule by the subscripts in the formula:

C_{6}=6*(12.01g)=72.06g

H_{12}=12*(1.008g)=12.096g

O_{6}=6*(15.999g)=95.994g

Then you add all of them together:

72.06g+12.096g+95.994g=180.15g

Therefore, the molar weight of glucose is 180.15 grams.

3 0
3 years ago
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