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zmey [24]
4 years ago
13

If the half-life of a radioisotope is 10,000 years, the amount remaining after 20,000 years is

Chemistry
1 answer:
Cloud [144]4 years ago
6 0

Answer:

Considering the half-life of 10,000 years, after 20,000 years we will have a fourth of the remaining amount.

Explanation:

The half-time is the time a radioisotope takes to decay and lose half of its mass. Therefore, we can make the following scheme to know the amount remaining after a period of time:

Time_________________ Amount

t=0_____________________x

t=10,000 years____________x/2

t=20,000 years___________x/4

During the first 10,000 years the radioisotope lost half of its mass. After 10,000 years more (which means 2 half-lives), the remaining amount also lost half of its mass. Therefore, after 20,000 years, the we will have a fourth of the initial amount.

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The equations given in the problem introduction can be added together to give the following reaction: overall: N2O4→2NO2 However
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Answer:

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Explanation:

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As can be seen, in the overall reaction we have N_2O_4 in the reactants like in the second reaction and NO_2 in the products. The NO_2 is in the first reaction but as a reactant so we need to reverse that reaction:

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