Answer: 79.6 g
mwof 02 is 16 and mw of H2O is 18.
Answer:
39.6 mL
Explanation:
Step 1: Write the balanced neutralization reaction
Ba(OH)₂(aq) + 2 CH₃COOH(aq) ⟶ Ba(CH₃COO)₂(aq) + 2 H₂O(l)
Step 2: Calculate the moles corresponding to 2.78 g of CH₃COOH
The molar mass of CH₃COOH is 60.05 g/mol.
2.78 g × 1 mol/60.05 g = 0.0463 mol
Step 3: Calculate the moles of Ba(OH)₂ needed to react with 0.0463 moles of CH₃COOH
The molar ratio of Ba(OH)₂ to CH₃COOH is 1:2. The moles of Ba(OH)₂ needed are 1/2 × 0.0463 mol = 0.0232 mol.
Step 4: Calculate the volume of 0.586 M solution that contains 0.0232 moles of Ba(OH)₂
0.0232 mol × 1 L/0.586 mol = 0.0396 L = 39.6 mL
Answer:
The molarass of Carbon carbide is 64.0 g/mol
Answer: Option (b) is the correct answer.
Explanation:
Atomic number of magnesium is 12 and its electronic distribution is 2, 8, 2. Whereas atomic number of sulfur is 16 and its electronic distribution is 2, 8, 6.
So, in order to attain stability a magnesium atom needs to lose its 2 valence electrons and a sulfur atom needs to gain two electrons to completely fill its octet.
Hence, magnesium on losing two electrons will acquire a +2 charge and thus, it becomes a cation. On the other hand, sulfur on gaining two electrons will acquire a -2 charge and thus, sulfur will become an anion.
Thus, we can conclude that in the reaction between magnesium and sulfur, the magnesium atoms become cations.
