Answer:
1. 39.997 g/mol
2. 6.022⋅1023 atoms of aluminium
3. 0.026 moles
4. 14 grams is the molar mass of nitrogen meaning that one mole of nitrogen atoms is 14 grams. One mole of any substance has 6.02*10^23 atoms/molecules of that subtance therefore there are 6.02*10^23 atoms of nitrogen in 14g of nitrogen
5. 78.5
Explanation:
Answer:
1s^2 2s^2 2p^6 3s^1
Explanation:
electron configuration of an element gives description of the distribution of electron in it's orbital of the atom, the superscript symbolize number of electron been hold by them.
The element here is sodium, which is a alkali metal
mass number =23
Number of proton= 11
electron must be seen in thelowest-energy subshell that is available in the the 3s orbital,
Hence, the electronic configuration is
1s^2 2s^2 2p^6 3s^1
Answer:
Through transport proteins
Explanation:
There's two transport proteins, channel/pore protein and carrier protein. Charged/polar molecules or ions need specific transport proteins to pass through across the plasma membrane. Transport proteins allows ions/polar molecules to bind to the specific site and allow them to pass through and enter the cell.
(btw, is this a chemistry question? isn't this a biology ques?)
Answer:
950mL
Explanation:
The following were Data were obtained from the question:
Initial volume (V1) = 100mL
Initial pressure (P1) = stp = 760mmHg
Final pressure (P2) = 80mmHg
Final volume (V2) =..?
The final volume of the gas can be obtained by using the Boyle's law equation as follow:
P1V1 = P2V2
760 x 100 = 80 x V2
Divide both side by 80
V2 = (760 x 100) /80
V2 = 950mL
Therefore, the new volume of the gas is 950mL
<u>Answer:</u> The concentration of hydrogen gas at equilibrium is 
<u>Explanation:</u>
We are given:
Initial moles of hydrogen sulfide gas = 0.47 moles
Volume of the container = 3.0 L
The molarity of solution is calculated by using the equation:

So, 
The given chemical equation follows:

<u>Initial:</u> 0.1567
<u>At eqllm:</u> 0.1567-2x 2x x
The expression of
for above equation follows:
![K_c=\frac{[H_2]^2[S_2]}{[H_2S]^2}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BH_2%5D%5E2%5BS_2%5D%7D%7B%5BH_2S%5D%5E2%7D)
We are given:

Putting values in above equation, we get:

So, equilibrium concentration of hydrogen gas = 
Hence, the concentration of hydrogen gas at equilibrium is 