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mafiozo [28]
3 years ago
9

A car travels at 60 m/s for 8 seconds. Calculate the distance it traveled.

Chemistry
1 answer:
soldi70 [24.7K]3 years ago
3 0

480 meters

hope this helped!

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100 POINTS PLEASE HELP
Gennadij [26K]

Answer:

1. 39.997 g/mol

2. 6.022⋅1023 atoms of aluminium

3. 0.026 moles

4. 14 grams is the molar mass of nitrogen meaning that one mole of nitrogen atoms is 14 grams. One mole of any substance has 6.02*10^23 atoms/molecules of that subtance therefore there are 6.02*10^23 atoms of nitrogen in 14g of nitrogen

5. 78.5

Explanation:

6 0
3 years ago
What is the electronic structure of an atom with a proton number 11 and mass number 23
MAXImum [283]

Answer:

1s^2 2s^2 2p^6 3s^1

Explanation:

electron configuration of an element gives description of the distribution of electron in it's orbital of the atom, the superscript symbolize number of electron been hold by them.

The element here is sodium, which is a alkali metal

mass number =23

Number of proton= 11

electron must be seen in thelowest-energy subshell that is available in the the 3s orbital,

Hence, the electronic configuration is

1s^2 2s^2 2p^6 3s^1

6 0
3 years ago
How do charged molecules pass through the membrane.
avanturin [10]

Answer:

Through transport proteins

Explanation:

There's two transport proteins, channel/pore protein and carrier protein. Charged/polar molecules or ions need specific transport proteins to pass through across the plasma membrane. Transport proteins allows ions/polar molecules to bind to the specific site and allow them to pass through and enter the cell.

(btw, is this a chemistry question? isn't this a biology ques?)

6 0
2 years ago
A sample of gas occupies 100.0 mL at standard pressure. What volume will the gas occupy at a pressure of 80.0 mm Hg if the tempe
Bogdan [553]

Answer:

950mL

Explanation:

The following were Data were obtained from the question:

Initial volume (V1) = 100mL

Initial pressure (P1) = stp = 760mmHg

Final pressure (P2) = 80mmHg

Final volume (V2) =..?

The final volume of the gas can be obtained by using the Boyle's law equation as follow:

P1V1 = P2V2

760 x 100 = 80 x V2

Divide both side by 80

V2 = (760 x 100) /80

V2 = 950mL

Therefore, the new volume of the gas is 950mL

8 0
4 years ago
2 H2S(g) ⇄ 2 H2(g) + S2(g) Kc = 9.3× 10-8 at 400ºC 0.47 moles of H2S are placed in a 3.0 L container and the system is allowed t
Anon25 [30]

<u>Answer:</u> The concentration of hydrogen gas at equilibrium is 1.648\times 10^{-3}M

<u>Explanation:</u>

We are given:

Initial moles of hydrogen sulfide gas = 0.47 moles

Volume of the container = 3.0 L

The molarity of solution is calculated by using the equation:

\text{Molarity}=\frac{\text{Moles of solute}}{\text{Volume of the solution}}

So, \text{Initial molarity of hydrogen sulfide gas}=\frac{0.47}{3}=0.1567M

The given chemical equation follows:

                          2H_2S(g)\rightleftharpoons 2H_2(g)+S_2(g)

<u>Initial:</u>                  0.1567

<u>At eqllm:</u>           0.1567-2x       2x         x

The expression of K_c for above equation follows:

K_c=\frac{[H_2]^2[S_2]}{[H_2S]^2}

We are given:

K_c=9.3\times 10^{-8}

Putting values in above equation, we get:

9.3\times 10^{-8}=\frac{(2x)^2\times x}{(0.1567-2x)^2}\\\\x=8.24\times 10^{-4}

So, equilibrium concentration of hydrogen gas = 2x=(2\times 8.24\times 10^{-4})=1.648\times 10^{-3}M

Hence, the concentration of hydrogen gas at equilibrium is 1.648\times 10^{-3}M

7 0
3 years ago
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