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3 years ago

What is the value of the expression below?

Mathematics

1 answer:

saw5 [17]3 years ago

6 0

Answer:

Step-by-step explanation:

$a^\frac{m}{n}=\bigg(\sqrt[n]{a}\bigg)^m\\\\(-8)^\frac{2}{3}=\bigg(\sqrt[3]{-8}\bigg)^2=(-2)^2=4$

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Round to the nearest thousandth:9.4048

vesna_86 [32]

Answer:

9.405

Step-by-step explanation:

7 0

2 years ago

Determine what type of model best fits the given situation:

lyudmila [28]

Let value intially be = P

Then it is decreased by 20 %.

So 20% of P = $\frac{20}{100} \times P = 0.2P$

So after 1 year value is decreased by 0.2P

so value after 1 year will be = P - 0.2P (as its decreased so we will subtract 0.2P from original value P) = 0.8P-------------------------------------(1)

Similarly for 2nd year, this value 0.8P will again be decreased by 20 %

so 20% of 0.8P = $\frac{20}{100} \times 0.8P = (0.2)(0.8P)$

So after 2 years value is decreased by (0.2)(0.8P)

so value after 2 years will be = 0.8P - 0.2(0.8P)

taking 0.8P common out we get 0.8P(1-0.2)

= 0.8P(0.8)

$=P(0.8)^{2}$ -------------------------(2)

Similarly after 3 years, this value $P(0.8)^{2}$ will again be decreased by 20 %

so 20% of $P(0.8)^{2} \frac{20}{100} \times P(0.8)^{2} = (0.2)P(0.8)^{2}$

So after 3 years value is decreased by $(0.2)P(0.8)^{2}$

so value after 3 years will be = $P(0.8)^{2} - (0.2)P(0.8)^{2}$

taking $P(0.8)^{2}$ common out we get $P(0.8)^{2}(1-0.2)$

$P(0.8)^{2}(0.8)$

$P(0.8)^{3}$ -----------------------(3)

so from (1), (2), (3) we can see the following pattern

value after 1 year is P(0.8) or $P(0.8)^{1}$

value after 2 years is $P(0.8)^{2}$

value after 3 years is $P(0.8)^{3}$

so value after x years will be $P(0.8)^{x}$ ( whatever is the year, that is raised to power on 0.8)

So function is best described by exponential model

$y = P(0.8)^{x}$ where y is the value after x years

so thats the final answer

3 0

3 years ago

Write negations for each of the following statements. (Assume that all variables represent fixed quantities or entities, as appr

amm1812

Answer:

a. P is a square and P is not a rectangle

b. Today is New Year’s Eve and tomorrow is not January.

c. The decimal expansion of r is terminating and r is not rational.

d. n is prime and either n is not odd or n is not 2.

e. x is nonnegative and either x is not positive or x is not 0.

f. Tom is Ann’s father and either Jim is not her uncle or Sue is not her aunt.

g. n is divisible by 6 and either n is not divisible by 2 or n is not divisible by 3.

Step-by-step explanation:

The general formula for negations that will be applied is:

Statement: If x is y, then x is z

Negation: x is y and x is not z

Statement: If x is y, then x is z and w

Negation: x is y and either x is not z or x is not w

Applying those principles:

a. P is a square and P is not a rectangle

b. Today is New Year’s Eve and tomorrow is not January.

c. The decimal expansion of r is terminating and r is not rational.

d. n is prime and either n is not odd or n is not 2.

e. x is nonnegative and either x is not positive or x is not 0.

f. Tom is Ann’s father and either Jim is not her uncle or Sue is not her aunt.

g. n is divisible by 6 and either n is not divisible by 2 or n is not divisible by 3.

4 0

3 years ago

16)<br> 1420<br> 2x<br> A) 67<br> C) 68<br> B) 71<br> D) 73<br><br> What is the value of x???

larisa [96]

Answer:

x = 710

Step-by-step explanation:

1. Divide both sides by 2 to get x by itself

1420 = 2x

↓

1420 ÷ 2 = 2x ÷ 2

↓

710 = x

2. Switch sides

710 = x

↓

x = 710

I know it is not one of your options but that is the answer to 1420 = 2x

3 0

3 years ago

The number of 7th graders attending Middle field Science Academy this year is 130% of last year’s total. If 500 7th graders atte

podryga [215]

Answer:

B. (100)(5)=500 C.(130)(5)=650 D.130/100= 650/500 E. There are 650 7th graders this year

Step-by-step explanation:

Just took it on Egde

6 0

3 years ago

Read 2 more answers