It could be express as (A) 14 x 10 to the tenth power or (b) 4.415 x 10 to the seventeenth power.
Answer:
Theta1 = 12° and theta2 = 168°
The solution procedure can be found in the attachment below.
Explanation:
The Range is the horizontal distance traveled by a projectile. This diatance is given mathematically by Vo cos(theta) t. Where t is the total time of flight of the projectile in air. It is the time taken for the projectile to go from starting point to finish point. This solution assumes the projectile finishes uts motion on the same horizontal level as the starting point and as a result the vertical displacement is zero (no change in height).
In the solution as can be found below, the expression to calculate the range for any launch angle theta was first derived and then the required angles calculated from the equation by substituting the values of the the given quantities.
<span>Energy exists as light, heat, sound, mass, moving objects, gravity, fuel, chemicals, and electricity.</span>
Answer:
A.REARRANGED AND FORM NEW SUBSTANCES WITH NEW PROPERTIES
Explanation:
Answer:
Answer is 519.3 J
Explanation:
GPE = m x g x h
Object Height is equal to 7.2 x sin42 = 7.2 x 0.669 = 4.817m
GPE = 11 x 9.8 x 4.817 =519.3 J
Most probably m value (11kg) has been used as 7.2 mistakenly.