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4 years ago

A boy performs 100 J of work pushing a chair a distance of 4 m. How much

Physics

1 answer:

olga55 [171]4 years ago

6 0

Answer:

25 N

Explanation:

Force can be found using the following formula.

F=w/d

where w is the work and d is the distance. We know that 100 Joules of work pushes the chair 4 meters. Therefore,

w=100 J

d= 4 m

F=100 J/ 4 m

Divide 100 by 4

100/4=25

F= 25 J/m

1 joule per meter, or J/m is equal to 1 Newton, or N.

F=25 N

The boy uses 25 Newtons of force.

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Brandon pushes an object on a ramp as shown in the diagram.

stiks02 [169]

The force which has the greatest effect on causing this object to slow while it remains in contact with the ramp is: B. a frictional force.

<h3>What is a force?</h3>

A force can be defined as a push or pull of an object or physical body, which typically results in a change of motion (acceleration), especially due to the interaction of the object with another.

<h3>The types of force.</h3>

In Science, there are different types of force and these include the following:

Gravitational force

Tension force.

Electrical force

Normal Force.

Magnetic force

Air resistance force

Applied force

Frictional force.

<h3>What is a frictional force?</h3>

Friction force can be defined as a type of force that resists and slows the relative motion of two physical objects when there surfaces come in contact. This ultimately implies that, a frictional force prevents two surfaces from easily sliding over or slipping across one another.

In this context, we can infer and logically deduce that the force which has the greatest effect on causing this object to slow while it remains in contact with the ramp is a frictional force.

Read more on frictional force here: brainly.com/question/25253774

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Complete Question:

Brandon pushes an object on a ramp as shown in the diagram.

While Brandon pushes the object and it remains in contact the ramp, which force has the greatest effect on causing it to slow?

A. the applied force

B. a frictional force

C. the force due to gravity

D. a force of air resistance

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2 years ago

A scientist is examining an unknown solid. Which procedure would most likely help determine a chemical property of the substance

Neporo4naja [7]

<span>procedure would most likely help determine a chemical property of the substance is : exposing it to a flame to see if it catches on fire Chemical property is the characteristic that a substance has that differntiate it with another substance. The most common charatcteristics that most scientists wanted to know are : - It's flamability - It's radioactivity - Its toxicity By throwing the object into fire, we will easily find out these 3 characteristics</span>

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3 years ago

Read 2 more answers

Objects with masses of 120 kg and a 420 kg are separated by 0.380 m. (a) Find the net gravitational force exerted by these objec

SOVA2 [1]

Answer:

$F_{net} = 6.879\times 10^{- 7}\ N$

Solution:

As per the question:

Mass of first object, m = 120 kg

Mass of second object, m' = 420 kg

Mass of the third object, M = 69.0 kg

Distance between the m and m', d = 0.380 m

Now,

To calculate the gravitational force on the object of mass, M placed mid-way due to mass, m:

$F = \frac{GMm}{\frac({d}{2}^{2})}$

$F = \frac{6.67\times 10^{-11}\times 120\times 0.69}{\frac({0.380}{2}^{2})} = 1.529\times 10^{- 7}\ N$

To calculate the gravitational force on the object of mass, M placed mid-way due to mass, m':

$F = \frac{GMm}{\frac({d}{2}^{2})}$

$F' = \frac{6.67\times 10^{-11}\times 420\times 0.69}{\frac({0.380}{2}^{2})} = 5.35\times 10^{- 7}\ N$

To calculate the gravitational force on the object of mass, M placed mid-way due to mass, m and m':

$F_{net} = F + F'$

$F_{net} = 1.529\times 10^{- 7} + 5.35\times 10^{- 7} = 6.879\times 10^{- 7}\ N$

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3 years ago

I need help with question two

zaharov [31]

I can't see numbers here, so here are all the answers:
1) the frequency is c/λ = 3e8/556e-9 = 5.39e14Hz
2) light travels at <span>299,792,458 m/s. So in nanoseconds it's 0.299792458m. This is about 1/3 of a meter which is about one foot.
3) length is L = ct = (</span>299,792,458 m/s)(6e-15) = 1.799e-6m or 1.799μm

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3 years ago

A car on a roller coaster starts at zero speed at an elevation above the ground of 26 m. It coasts down a slope, and then climbs

nirvana33 [79]

The speed of the car at the top of the hill is 14m/s

<u>Explanation:</u>

given that

Initial velocity u of the car=0 m/s

The distance can be determined by finding out the difference between the elevation of the first slope and second slope.

elevation of the first slope=26 m

elevation of second slope=16m

distance s=26-16=10 m

acceleration due to gravity g=9.8 m/s2

speed of the car at the top of the hill can be determined by using the equation

$v^2=u^2+2as\\v^2=0^2+2\times 9.8\times 10\\=196\\v=\sqrt{196} =14m/s$

speed of the car at the top of the hill is 14m/s

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3 years ago