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olga nikolaevna [1]
4 years ago
8

I need help on the ones that are blank they are to confusing

Physics
1 answer:
Pavel [41]4 years ago
3 0
For number 52, 1kg=1000 g

So, if she has 750 grams:

1,000g-750g= 250g

She would need 250g more soil

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Milk being heated on top of a stove will do what?
Temka [501]
The answer would be Expand because when a liquid is heated the molecules expand

Hope this helps

Have a great day/night
8 0
3 years ago
When a submarine dives to a depth of 5.0 × 102 m, how much pressure, in pa, must its hull be able to withstand? how many times l
nordsb [41]
<span>Depth = 5.0 Ă— 10^2 m
 Density of sea water = 1.025 x 10^3
 Pd = Po + pgh
Atmospheric pressure is standard Patm = 1.01325 x 10^5 Pa
  Since the normal pressure is retained in the hull, no need to bother about Po Pd = pgh = 1.025 x 10^3 x 9.8 x 5.0 x 10^2 = 50.225 x 10^5
 So now Pd / Patm = 50.225 x 10^5 / 1.01325 x 10^5 = 49.56
 So it is 49.56 times larger.</span>
5 0
3 years ago
Read 2 more answers
Allocate birr 5000 among the three workers in the ratio 1/3 :1/6 and 5/12.​
EastWind [94]

Answer:

1666.7 ETB (birr)

833.3 ETB (birr)

2083.3 ETB (birr)

Explanation:

The first worker

5000*1/3=1666.7

The second worker

5000*1/6=833.3

The third worker

5000*5/12=2083.3

Hope this helps :) ❤❤❤

3 0
3 years ago
Two forces P and Q acting at a point at an angle have their resultant
nasty-shy [4]

Answer:

Answer is given in this paper.

                                               <u><em>Thank You</em></u>

                                     Please mark me Brainlest.

6 0
3 years ago
A 1.50-V battery is used to charge a capacitor. When the capacitor is fully charged, it stores 64.0 mJ. If the capacitor were fu
Leona [35]

Answer:

0.256 J.

Explanation:

The formula for the energy stored in a capacitor is given as

E = 1/2CV².................... Equation 1

Where E = Energy stored in the capacitor, C = Capacitance of the capacitor, V = Voltage.

Make C the subject of the equation

C = 2E/V².................. Equation 2

Given: E = 64 mJ  = 0.064 J, V = 1.5 V.

Substitute into equation 2

C = 2(0.064)/(1.5²)

C = 0.128/2.25

C = 0.0569 F.

If the capacitor where fully charged by 3.00 V.

E = 1/2CV²

Given: C = 0.0569 F, V = 3.0 V

Substitute into the equation above,

E = 1/2(0.0569)(3²)

E = 0.256 J.

4 0
4 years ago
Read 2 more answers
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