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3 years ago

The orbital period of planet Venus is 0.62 years. What is its distance from the sun?

1 answer:

5 0

Kepler's third law shows the relationship between the orbital period of an object and the distance between the object and the object it orbits.

The simplified version of this law is: P^2 = a^3

Where,

P = period of the orbit in years = 0.62 years

a = average distance from the object to the object it orbits in AU. The astronomical unit AU is a unit of length which is roughly equivalent to the distance from Earth to the Sun.

Therefore calculating for a:

0.62 ^ 2 = a ^ 3

a = 0.62 ^ (2/3)

a = 0.727 AU = 0.72 AU

Therefore we can interpret this as: The distance from Venus to the Sun is about 72% of the distance from Earth to Sun.

<span>Answer: B. 0.72 AU</span>

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Consider two equal-volume flasks of gas at the same temperature and pressure. One gas, oxygen, has a molecular mass of 32. The o

san4es73 [151]

Answer: The ratio of the number of oxygen molecules to the number of nitrogen molecules in these flasks is 1: 1

Explanation:

According to avogadro's law, equal volumes of all gases at same temperature and pressure have equal number of moles.

According to avogadro's law, 1 mole of every substance contains avogadro's number $6.023\times 10^{23}$ of particles.

Thus as oxygen and nitrogen are at same temperature and pressure and are in equal volume flasks , they have same number of moles and thus have same number of molecules.

The ratio of the number of oxygen molecules to the number of nitrogen molecules in these flasks is 1: 1

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3 years ago

How many moles of gas are in 4.4 mL at 1.2 atm?

kirza4 [7]

The Correct Answer Is 3.2

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3 years ago

How can you write tht in mg ??

inessss [21]

Rris is how u right it Mg=? Because it ask u a question and then you put the equal sign and then you put the question mark because you don't know it yet

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3 years ago

Read 2 more answers

Formation of water: 2H2 + 1 O2 --> 2H2O

noname [10]

Answer:

2.2 moles H2O

Explanation:

$35g O_2 \mbox{ \cdot }\frac{1mol}{32g/mol} \mbox{ \cdot }\frac{2mol H_2O}{1mol O_2}= 2.1875$ , which rounds to about 2.2

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2 years ago

Would precipitation occur when 500 mL of a 0.02M solution of AgNO3 is mixed with 500 mL of a 0.001M solution of NaCl? Show your

Oksanka [162]

We know,
AgNO3 + NaCl ⇒ NaNO3 + AgCl(s)
The moles of Na+ present:
0.5 L * 0.001 mol/L
= 5 x 10⁻⁴ mol
Moles of Ag+ present:
0.5 * 0.02
= 0.01 mol
The limiting reactant is Na
Therefore, the moles of Ag reacted:
5 x 10⁻⁴
AgCl is insoluble in water; therefore, the AgCl formed will precipitate

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3 years ago