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never [62]
3 years ago
14

The orbital period of planet Venus is 0.62 years. What is its distance from the sun?

Chemistry
1 answer:
Vikki [24]3 years ago
5 0

Kepler's third law shows the relationship between the orbital period of an object and the distance between the object and the object it orbits.

The simplified version of this law is: P^2 = a^3

Where,

P = period of the orbit in years = 0.62 years

a = average distance from the object to the object it orbits in AU. The astronomical unit AU is a unit of length which is roughly equivalent to the distance from Earth to the Sun.

Therefore calculating for a:

0.62 ^ 2 = a ^ 3

a = 0.62 ^ (2/3)

a = 0.727 AU = 0.72 AU

Therefore we can interpret this as: The distance from Venus to the Sun is about 72% of the distance from Earth to Sun.

<span>Answer: B. 0.72 AU</span>

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What volume will water vapor form when 40 liters of hydrogen completely reacts with 25 liters of oxygen? Assume the temperature
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number of moles in reaction                 2 mol                  1 mol       2 mol
number of liters in the reaction         2*22.4 L                1*22.4 L    2*22.4L
We can see that volumes of the gases are proportional to coefficients in the reaction ( if gases are under the same conditions), so we can write

                              2H2           +           O2 ---->2H2O  
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     given                 40 L                      ( 25 L)     40 L

We can see that we have excess of O2,
because if 2 L H2 are needed 1 L O2, then 40 L of H2 are needed 20 L O2.

So, limiting reactant is H2, and we will need to calculate Volume of H2O using H2.
2L H2 give 2L H2O(gas), so 40 L H2 give 40 L H2O.
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Energy pyramid worksheet
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Answer:

From top to bottom coyote, crow, squirrel, then acorn

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Consider the decomposition of red calx of mercury (HgO) into its elements as follows:
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Part A. Two containers, one at 305 K and the other at 295 K, are placed in contact with each other. 1. 1 J of heat flows from th
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0.00011 JK.

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Explanation:

The following parameters are given which are going to help in solving for the change in entropy of the system. The term "entropy'' simply means the degree of disorderliness of a system.

=> The temperature of container A = 305 K, the temperature of container B = 295 K and the amount of heat generated when the containers are placed in contact with each other = 1. 1 J.

The change in entropy of the hot container = -(1/305) = - 0.00328 J/K.

The change in entropy of the cold container = 1/295 = 0.00339 J/K.

Therefore, the change in the entropy of the system = - 0.00328 J/K + 0.00339 J/K = 0.00011 JK.

Note that the change in entropy of the system gives a positive value. Hence, this process does not violate the second law of thermodynamics.

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I hope this helps :)

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