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Katarina [22]
3 years ago
5

How is the concept of “heat” related to the law of conservation of energy?

Chemistry
1 answer:
musickatia [10]3 years ago
5 0

Explanation:

The law of conservation of energy states that energy can neither be created nor destroyed - only converted from one form of energy to another. This means that a system always has the same amount of energy, unless it's added from the outside. ... is the heat added to, or removed from, the system.

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Point E is located at (-2, 2) and point F is located at (4-6). What is the distance between
Flauer [41]

Answer:

10

Explanation:

Given endpoints:

            E (-2,2) and F(4, -6)

To find the distance between two points;

   Use the expression below;

 D = \sqrt{(y_{2} - y_{1}  )^{2} + (x_{2} -  x_{1})^{2}  }

x₁  = -2,

x₂ = 4

y₁ = 2

y₂ = -6

  Insert the parameters and solve;

       D = \sqrt{(-6 - 2  )^{2} + (4 -+ 2)^{2}  }

      D = \sqrt{64+ 36 }   = 10

5 0
3 years ago
Why do your feet feel cooler on a tile floor than on a warm rug?
stira [4]
<span>The rug is a better insulator than the tile</span>
6 0
3 years ago
Read 2 more answers
Lead thiocyanate, Pb(SCN)2, has a Ksp value of 2.00×10−5.a) Calculate the molar solubility of lead thiocyanate in pure water. Th
kkurt [141]

Answer:

a) 1.71 × 10⁻³ M

b) 8.00 × 10⁻⁵ M

Explanation:

In order to calculate the solubility (S) of Pb(SCN)₂ we will use an ICE chart. We identify 3 stages (Initial, Change, Equilibrium) and complete each row with the concentration or change in the concentration.

       Pb(SCN)₂(s) ⇄ Pb²⁺(aq) + 2 SCN⁻(aq)

I                                 0                   0

C                               +S               +2S

E                                 S                  2S

The solubility product (Ksp) is:

Ksp = 2.00 × 10⁻⁵ = [Pb²⁺].[SCN⁻]² = S . (2S)² = 4S³

S = 1.71 × 10⁻³ M

<em>b) Calculate the molar solubility of lead thiocyanate in 0.500 M KSCN.</em>

KSCN is a strong electrolyte that dissociates to give 0.500 M K⁺ and 0.500M SCN⁻.

       Pb(SCN)₂(s) ⇄ Pb²⁺(aq) + 2 SCN⁻(aq)

I                                 0                 0.500

C                               +S                +2S

E                                 S                0.500 + 2S

Ksp = 2.00 × 10⁻⁵ = [Pb²⁺].[SCN⁻]² = S . (0.500 + 2S)²

In the term (0.500 + 2S)², 2S is negligible.

Ksp = 2.00 × 10⁻⁵ = S . (0.500)²

S = 8.00 × 10⁻⁵ M

4 0
3 years ago
What is a half-life?
Travka [436]

Answer:

An interesting and useful aspect of radioactive decay is half-life, which is the amount of time it takes for one-half of a radioactive isotope to decay. The half-life of a specific radioactive isotope is constant; it is unaffected by coTnditions and is independent of the initial amount of that isotope.

Explanation:

4 0
3 years ago
For the following experiment, write a possible hypothesis, and then identify the independent variable, dependent variable, and c
katovenus [111]
1st question:
possible hypothesis: What is the fastest route to drive through to reach the youth group?
Independent variable: This would be the speed of the car she will be driving.
Dependent variable: The length of time it would take Susan to arrive in her destination using each route.
Controlled variable: The speed of the car she will be driving. This should remain constant in every route she takes. 

2nd question: 
What cooking spray best keeps food from sticking to a pan?

Dan used different independent variables and dependent variables. There is nothing to compare in each experiment because there is no controlled variable.

breakfast: grape seed oil in a pan to cook eggs.
lunch: vegetable oil spray in a muffin tray to cook cornbread
dinner: olive oil in a pan to cook a hamburger patty.

The cooking oil used are not all in spray form. The pan is only used in two occasions. Different type of food were cooked. 

Dan should used cooking oils in spray form. He should also use only one pan and only one type of food to determine whether said food will stick to the pan using a certain cooking oil spray.
3 0
3 years ago
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