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pashok25 [27]
3 years ago
14

The chance of rain on a randomly selected day in Western Oregon between June 21st and September 21st is 30% each day. What is th

e probability it rains at least 2 out of any randomly selected 5 days during the given time of year? (round your answer to the nearest hundredth)
Mathematics
1 answer:
polet [3.4K]3 years ago
6 0

Answer:

0.47 is the probability it rains at least 2 out of any randomly selected 5 days during the given time of year

Step-by-step explanation:

We are given the following information:

We treat training as a success.

P(Rain) = 30% = 0.30

Then the chances of rain on each day follows a binomial distribution, where

P(X=x) = \binom{n}{x}.p^x.(1-p)^{n-x}

where n is the total number of observations, x is the number of success, p is the probability of success.

Now, we are given n = 5

We have to evaluate:

P(x \geq 2) =1- P(x = 0) + P(x = 1) \\=1- \binom{5}{0}(0.3)^0(1-0.3)^5 - \binom{5}{1}(0.3)^1(1-0.3)^4\\=1- 0.16807- 0.36015\\= 0.47178 \approx 0.47

0.47 is the probability it rains at least 2 out of any randomly selected 5 days during the given time of year

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Do oddsmakers believe that teams who play at home will have home field advantage? Specifically, do oddsmakers give higher point
anygoal [31]

Complete question is;

Do oddsmakers believe that teams who play at home will have home field advantage? Specifically, do oddsmakers give higher point spreads when the favored team plays home games as compared to when the favored team plays away games?

Two samples were randomly selected from three complete National Football League seasons (1989, 1990, and 1991). The first sample consisted of 50 games, where the favored team played in a home game, while the second sample consisted of 50 games, where the favored team played in an away game. The oddsmakers’ point spreads (which are the number of points by which the favored team is predicted to beat the weaker team) were then collected.

If µ1 and µ2 represent the mean point spread for home games and away games, respectively, which of the following is the appropriate.

A) H0: μ1 - μ2 = 0

Ha: μ1 - μ2 < 0

B) H0: μ1 - μ2 = 0

Ha: μ1 < μ2

C) H0: μ1 - μ2 > 0

Ha: μ1 - μ2 = 0

D) H0: μ1 - μ2 = 0

Ha: μ1 - μ2 > 0

E) None of the above

Answer:

D) H0: μ1 - μ2 = 0

Ha: μ1 - μ2 > 0

Step-by-step explanation:

We want to find out if oddsmakers give higher point spreads when the favored team plays home games as compared to when the favored team plays away games.

Now, since µ1 and µ2 represent the mean point spread for home games and away games, respectively;

It means we want to find out if µ1 > µ2 as the alternative hypothesis.

Thus, alternative hypothesis is;

Ha: µ1 - µ2 > 0

Meanwhile null hypothesis assumes that equal point spreads are given when the favored team plays home games as well as when the favored team plays away games.

Thus, null hypothesis is;

H0: μ1 - μ2 = 0

The only correct option is D.

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