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Stels [109]
4 years ago
12

Philip rolls a stranded number cube 24 times. which is the best prediction for the number of times he will roll a number that is

even and less then 4?
Mathematics
1 answer:
timofeeve [1]4 years ago
5 0
Divide 24 by 6 because that is how many numbers are on the cube which would equal 4
Then multiply 4 and 2 because that's how many possibilities there are of rolling a number less than 4 and is even and the solution is 8
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4 cm
pentagon [3]

Answer:

do we have to find area?

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
What is the median of the data set given below?
Bumek [7]
The median is 26 because if you put the numbers in order it’s 18,21,21,24,26,35,39,48 and the list of numbers is even so you can take out one of the 21 and the you get only 7 sets of numbers and the middle number is 26
4 0
3 years ago
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Does anyone know how to answer this question I'm having a lot of trouble with it?
Helen [10]

Answer:

h = \frac{2A}{(b+c)}

Step-by-step explanation:

Formula for the area of a trapezoid is,

Area (A) = \frac{1}{2}(b+c)h

Here b and c are the bases and 'h' is the height of the trapezoid.

2A = 2[\frac{1}{2}(b+c)h]

2A = (b + c)h

\frac{2A}{(b+c)}=h

Therefore, formula for the height of the trapezoid will be,

h = \frac{2A}{(b+c)}

5 0
3 years ago
It took Sheldon 17 5/6 minutes to walk to Raj's house. The bus ride home took Sheldon 4 5/8 minutes. How many more minutes did i
MA_775_DIABLO [31]

Answer:

it will take her  13\frac{5}{24} minutes more to walk down to Raj's House

Step-by-step explanation:

It took Sheldon 17 \frac{5}{6}  minutes to walk to Raj's house

It also took Sheldon 4\frac{5}{8} minutes to use the bus.

To get the time difference between the two transport mechanisms, we subtract their different time durations.

This will be

17\frac{5}{6} - 4\frac{5}{8}=317/24

We can convert this to Mixed fractions as shown 13\frac{5}{24} minutes.

Therefore, it will take her  13\frac{5}{24} minutes more to walk down to Raj's House

4 0
3 years ago
PLEASE HELP ME!!
Grace [21]
Take the derivative:
g’(x) = 12x^3 - 24x^2

Set equal to zero and solve:
0 = 12x^3 - 24x^2
0 = 12x^2 (x - 2)

x = 0 or x = 2

Plug back into original
g(0) = 3(0^4) - 8(0^3)
g(0) = 0 - 0
g(0) = 0

g(2) = 3(2^2) - 8(2^3)
g(2) = 3(4) - 8(8)
g(2) = 12 - 64
g(2) = -52

There is an absolute max at (0,0) or when x = 0
5 0
3 years ago
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